SQL：比较来自两个不同选择的两个结果

Question

我需要确定我们的顾问是否正确记录了他们的工作。为此，我有两个不同的来源：一个包含来电，另一个在我们的客户系统中其日志。

呼叫链接到电话号码，日志链接到客户号码。对于这两个来源中的每一个，我都有一个选择，可为我提供每个顾问的周号和（客户/电话）号的不同组合的数目，以查找整年的唯一“周通话”总数。但是，如何将唯一日志的结果与唯一调用相除？而且对于奖金难度，没有临时表格（在Excel中无效）

选择＃1

SELECT 
count(distinct(concat(datepart(ww,call_datetime),phonenumber))) as 
calls,consultant
FROM calltabel
group by consultant

选择＃2

SELECT 
count(distinct(concat(datepart(ww,log_datetime),phonenumber))) as 
logs,consultant
FROM logtabel
group by consultant

结果

选择＃1

consultant    calls
eric          10
kimmie        20

选择＃2

consultant    logs
eric          5
kimmie        20

组合结果应该是

consultat    calls    logs     result
eric         10        5        0.5
kimmie       20       20        1.0  

Answer 1

您可以像这样加入查询

select t1.consultant, calls, logs, logs/calls as result
(SELECT 
count(distinct(concat(datepart(ww,call_datetime),phonenumber))) as 
calls,consultant
FROM calltabel
group by consultant) as t1
inner join
(SELECT 
count(distinct(concat(datepart(ww,log_datetime),phonenumber))) as 
logs,consultant
FROM logtabel
group by consultant) as t2 on t1.consultant=t2.consultant

或者您可以这样做：

select t1.consultant, calls, logs, logs/calls as result from
(
SELECT calltabel.consultant,
count(distinct(concat(datepart(ww,call_datetime),phonenumber))) as calls,
count(distinct(concat(datepart(ww,log_datetime),phonenumber))) as logs    
FROM calltabel 
inner join logtabel on logtabel.consultant= calltabel.consultant
group by calltabel.consultant
)

Answer 2

You can do inner join:

Select callTable.Consultant, callTable.calls, logTable.logs, logTable.logs/callTable.logs as ‘Result’ from (SELECT 
count(distinct(concat(datepart(ww,call_datetime),phonenumber))) as 
calls,consultant
FROM calltable
group by consultant) as callTable, (SELECT 
count(distinct(concat(datepart(ww,log_datetime),phonenumber))) as 
logs,consultant
FROM logtable
group by consultant) as logTable

Where logTable.consultant = callTable.consultant;