Question

该程序的后两个规范出现问题。

1）格瑟（Guesser）最初有6个未中（第7次进攻他们被淘汰）。如果他们赢得了这场比赛，他们将再次比赛，但只有5次未中，依此类推。当他们未能以指定的猜测数猜出单词或直到赢得0次未中的游戏时，游戏即告结束。

-我已经尝试过，但是我不知道如何让其他函数中的所有数字反映新的变化。我想保留重播选项，以便他们可以随时退出。

2）在每个猜测之前，显示尚未被猜测的字母列表。

-我知道这比较简单，应该知道，但是我认为我已经动了脑筋。

我还有文档要做，对于任何错误我深表歉意。任何清理总是值得赞赏的。预先感谢。

import random
import string

word_list = ["no", "hi", "bee", "car", "seat", "bear", "see", "chip"]
available_letters = string.ascii_lowercase  # pop guessed letter from here
used_letters = []  # Add it to here, and display avaiable_letters each time a letter is guessed.


missed_letters = ""
correct_letters = ""
secret_word = random.choice(word_list).lower()


def get_random(word_list):

    secret_word = random.choice(word_list).lower()
    return secret_word


def display_board(missed_letters, correct_letters, secret_word):

    print("Current Score:")

    for letter in missed_letters:
        print(letter)
    print()

    blanks = '-' * len(secret_word)

    for i in range(len(secret_word)):
            if secret_word[i] in correct_letters:
                blanks = blanks[:i] + secret_word[i] + blanks[i+1:]

    for letter in blanks:
        print(letter)
    print()


def get_player_guess(guessed):

    while True:
        guess = input("Enter a letter: ")  # try guess = input(blah blah).lower()
        guess = guess.lower()

        if len(guess) != 1:
            print("1 Letter at a time!")
        elif guess in guessed:
            print("Whoops, you already guessed that one!")
        elif guess not in "abcdefghijklomnopqrstuvwxyz":
            print("Letters only please!")
        else:
            return guess


def replay_game():

    replay = input("Do you want to play again? y or n ")

    if replay == "y":
        play_game(missed_letters, correct_letters, secret_word)
    else:
        print("Bye!")


def play_game(missed_letters, correct_letters, secret_word):

    count = 0
    chance = 7
    game_over = False

    print("Welcome To Hangman.")

    while True:
        display_board(missed_letters, correct_letters, secret_word)

        guess = get_player_guess(missed_letters + correct_letters)

        if guess in secret_word:

            correct_letters = correct_letters + guess

            done = True

            for i in range(len(secret_word)):
                    if secret_word[i] not in correct_letters:
                        done = False
                        break

            if done:
                print("You win!")
                game_over = True
        else:

            missed_letters = missed_letters + guess

            count += 1
            chance -= 1

            if count == 1:
                print("You've got " + str(count) + " Strike. You have " + str(chance) + " Chances left")
            elif count > 1 and count < 6:
                print("You've got " + str(count) + " Strikes.  You have " + str(chance) + " Chances left")
            elif count == 6 and chance == 1:
                print("You've got " + str(count) + " Strikes.  You have " + str(chance) + " Chance left")

            if len(missed_letters) == 7:

                display_board(missed_letters, correct_letters, secret_word)

                print("Sorry!  You've run out of guesses! The right word was " + secret_word + "!")

                game_over = True

        if game_over:

            if replay_game():
                missed_letters = ""
                correct_letters = ""
                secret_word = get_random(word_list)

            else:
                break


play_game(missed_letters, correct_letters, secret_word)

Answer 1

目前，您不会更改replay_game时的单词，因为永远不会调用结尾if replay_game之后的文本。

对于第一个问题，我会将游戏的总机会记录为play_game的输入变量，并将replay_game更改为仅返回true或false并将其他代码移至play_game

def replay_game():

    replay = input("Do you want to play again? y or n ")
    # Changed to just return true or false depending on input.
    if replay == "y":
        return True
    else:
        print("Bye!")
        return False

然后将play_game的开始更改为

def play_game(missed_letters, correct_letters, secret_word, total_chances=7):

    count = 0
    # chance is now variable
    chance = total_chances
    game_over = False

并在play_game的末尾替换：

if len(missed_letters) == 7:

使用

if chance == 0:

并将呼叫if game_over更改为

if game_over:

    if replay_game():
        missed_letters = ""
        correct_letters = ""
        secret_word = get_random(word_list)
        play_game(missed_letters, correct_letters, secret_word, total_chances - 1)

    else:
        break

这将意味着您正在重置字母的代码将立即被调用，并且每个重新启动的游戏开始的机会都比前一个少。

您必须添加一些处理，以防止他们获胜而不允许错过。

对于第二个问题，只需将以下内容添加到显示板中即可：

print("Available letters:")
print(','.join(sorted(set(available_letters) - set(missed_letters) - set(correct_letters))))

这将三组字母中的每组组成一组，然后除去已经猜出的字母，然后将它们按一行显示，按字母顺序排序并以逗号分隔。

Answer 2

关于函数display_board，我会稍稍清理一下代码，以便在正确猜中的情况下用正确的字母替换空格中的'_'：

for i in range(len(secret_word)):
            if secret_word[i] in correct_letters:
                blanks[i] = secret_word[i]

看起来更干净，并且空白元素的重新分配更少。

从列表中弹出并从函数中减去（Hangman）

2 个答案: