Xamarin SQLite DB错误（嵌入式资源）

Question

我正在尝试 SQLite 嵌入的资源，但是我遇到了很多困难。问题是臭名昭著的“找不到表”，但看来我的方向不对。

首先，这是我当前的代码：

        string filename = "Testing.CSV." + items[category][subcategory].file + "-" + App.current_language + ".db3";

        var conn = new SQLiteConnection(filename);

        var o = conn.GetTableInfo("Items");
        var q = conn.Table<Items>().Where(x => (x.thenumber > 3 && x.thenumber < 20));

        List<Items> u = conn.Table<Items>().ToList();
        foreach(var i in q)
        {
            System.Diagnostics.Debug.Print("LINQ returned int {0} string '{1}'", i.thenumber, i.thelabel);
        }

        var p = conn.Query<int>("select thenumber from Items where thenumber > 3 and thenumber< 20 order by random() limit 1;", 1);

在创建连接后添加conn.CreateTable<Items>();不会有任何帮助，除了掩盖错误：我没有得到空指针，但是我没有从任何查询中得到任何结果< / strong>您在上方看到了。

将数据库的路径更改为以下内容也没关系：

        var embeddedResourceDbStream = Assembly.GetExecutingAssembly().GetManifestResourceStream(filename);
        var dbPath = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.Personal), filename);

        var conn = new SQLiteConnection(dbPath);

请注意，我对文本文件（也包含嵌入式资源）有相同的查询，它的工作原理就像一个超级按钮：

        string filename = "Testing.CSV." + items[category][subcategory].file + "-" + App.current_language + ".txt";

        var assembly = IntrospectionExtensions.GetTypeInfo(typeof(TestPage)).Assembly;
        Stream stream = assembly.GetManifestResourceStream(filename);
        StreamReader reader = new StreamReader(stream);

        // Good old CSV, at least I can open it
        List<string> lines = new List<string>(2);

        // Load all its contents and query
        while (!reader.EndOfStream)
        {
            string s = reader.ReadLine();

            // ...

消除任何疑问，SQLite DB在那里并且可以正常工作，至少手动查询在外壳中有效：

% sqlite3 /Users/sensei/Documents/Projects/playground/Testing/Testing/CSV/Test-en.db3 
SQLite version 3.24.0 2018-06-04 19:24:41
Enter ".help" for usage hints.
sqlite> select thenumber from Items where thenumber > 3 and thenumber< 20 order by random() limit 1;
19
sqlite> select thenumber from Items where thenumber > 3 and thenumber< 20 order by random() limit 1;
17
sqlite> select thenumber from Items where thenumber > 3 and thenumber< 20 order by random() limit 1;
8
sqlite> select thenumber from Items where thenumber > 3 and thenumber< 20 order by random() limit 1;
5
sqlite> 

我错过了我无法看到的非常明显的东西吗？