Question

我可以得到我的价值观，谢谢。

Answer 1

假设标签最终为["Pitcher","Pitcher","Catcher","Batter"];

const tags = ["Pitcher","Pitcher","Catcher","Batter"];
const result = Object.entries(tags.reduce((r,t)=>(r[t]=(r[t]||0)+1,r),{})).map(([k,v])=>`<li key="${k}">${k} - ${v}</li>`).join('\n');
console.log(result);

当然，由于您看不到标签的确切使用方式，因此很有可能标签更像

const tags = ["","Pitcher","","Pitcher","","Catcher","","Batter"];
const result = Object.entries(tags.reduce((r,t)=>(r[t]=(r[t]||0)+1,r),{})).map(([k,v])=>`<li key="${k}">${k} - ${v}</li>`).join('\n');
console.log(tags.join('')); // you can't see the empty tags here
console.log(result); // but this is the result

这就是为什么我要求您发布attendance是什么，以查看数据发生了什么情况

但是，按照我的建议使用过滤器...

const tags = ["","Pitcher","","Pitcher","","Catcher","","Batter"];
const result = Object.entries(tags.filter(t=>t).reduce((r,t)=>(r[t]=(r[t]||0)+1,r),{})).map(([k,v])=>`<li key="${k}">${k} - ${v}</li>`).join('\n');
console.log(tags.join('')); // you can't see the empty tags here
console.log(result); // with filter, everything is good again

Answer 2

如果tags是一个字符串数组（标签名称），则可以使用reduce来获得所需的输出。

示例

var tags = ['Pitcher', 'Pitcher', 'Catcher', 'Batter', 'Batter'];
var result = tags.reduce((acc, val) => {
  acc[val] = acc[val] || 0;
  acc[val] = acc[val] + 1;
  return acc;
}, {});
console.log(result);

希望这会有所帮助！

修改要将最终对象转换为字符串数组，可以使用.map

Object.entries(result).map(([k, v]) => `${k}-${v}`);

感谢Jaromanda X

获取总价值

2 个答案: