用不同的外键定义has_one

时间:2018-10-23 12:00:00

标签: ruby-on-rails activerecord

我有两个Rails模型,HubAdvisorHub的has_many Advisor像这样:

class Hub < ApplicationRecord
  has_many :advisors
end

我想将一个特定的Advisor设置为该中心的经理。我已经在集线器中添加了manager_id,如下所示:

class AddManagerToHub < ActiveRecord::Migration[5.1]
  def change
    change_table :hubs do |t|
      t.references :manager, references: :advisors
    end
  end
end

但是我无法找出在模型中设置此关系的正确方法。逻辑要求应该是:

has_one :manager, class_name: 'Advisor', primary_key: :manager_id

但是当我这样保存时:

hub.manager = advisor
hub.save

未设置集线器ID。有什么作用?

Hubs表的表结构为:

Column      |        Type         | Collation | Nullable |             Default              | Storage  | Stats target | Description 
------------------+---------------------+-----------+----------+----------------------------------+----------+--------------+-------------
id               | bigint              |           | not null | nextval('hubs_id_seq'::regclass) | plain    |              | 
name             | character varying   |           |          |                                  | extended |              | 
address_line_1   | character varying   |           |          |                                  | extended |              | 
address_line_2   | character varying   |           |          |                                  | extended |              | 
postcode         | character varying   |           |          |                                  | extended |              | 
longitude        | double precision    |           |          |                                  | plain    |              | 
latitude         | double precision    |           |          |                                  | plain    |              | 
ward_mapit_codes | character varying[] |           |          | '{}'::character varying[]        | extended |              | 
manager_id       | bigint              |           |          |                                  | plain    |              | 
Indexes:
"hubs_pkey" PRIMARY KEY, btree (id)
"index_hubs_on_manager_id" btree (manager_id)
Referenced by:
TABLE "advisors" CONSTRAINT "fk_rails_d86df62174" FOREIGN KEY (hub_id) REFERENCES hubs(id)

1 个答案:

答案 0 :(得分:1)

由于在集线器中添加了manager_id并引用了Advisor,因此关联应如下所示:-

class Hub < ApplicationRecord
  has_many :advisors
  belongs_to  :hub_manager, class_name => "Advisor", :foreign_key => "manager_id", optional: true
end

class Advisor < ApplicationRecord
  belongs_to :hub
  has_many :owned_hubs, class_name => "Hub", :foreign_key => "manager_id",
end

查询将类似于:-

hub.hub_manager = advisor
hub.save
相关问题