Question

我在程序中有2个列表。一个列表是5个泛型整数的列表，第二个列表包含5个用户输入的整数。现在，我需要比较每个用户号码是否在通用号码列表上。如果是这样，请向播放器添加一个点。我不知道从哪里开始。我真的不想要一个完整的答案，但是我找不到任何教程进行这种比较，因此，我将不胜感激。

import random



#Winning numbers
def winningNumbers():
  winning_numbers = []
  for i in range(5):
    x = random.randint(1,50)
    winning_numbers.append(x)
  print("Today's winning numbers are: " + str(winning_numbers))
  return winning_numbers

#Get player numbers
def player_numbers():
  user_input = []
  while len(user_input) < 5:
    number = input("Chose the numbers from 1-50:")
    try:
      number = int(number)
    except ValueError:
      print("That's not a number!")
      continue  
    if number in user_input:
      print("You already chosen this number!")  
    elif number not in range(1,51):
      print("The number is out of range")    
    else:
      user_input.append(number)
  print("Your chosen numbers are: " + str(user_input))
  return user_input
#Compare numbers
def compare_numbers():
  player_points = 0
  for i in winning_numbers:
    for x in user_input:
        if str(x) == str(y):
            player_points = player_points + 1
        else:
            pass
  print(player_points)  



winningNumbers()
player_numbers()
compare_numbers()

Answer 1

我能够从GeeksForGeeks Comparing Python Lists那里获得

该程序将打印出两个列表中都存在的元素。

# Python program to find the common elements  
# in two lists 
def common_member(a, b): 
    a_set = set(a) 
    b_set = set(b) 
    if (a_set & b_set): 
        print(a_set & b_set) 
    else: 
        print("No common elements")  


a = [1, 2, 3, 4, 5] # here is where you would gather the lists  
b = [5, 6, 7, 8, 9] 
common_member(a, b)

Answer 2

您可以做的最好的事情就是创建一个嵌套循环，这样就可以在一个循环中循环。这样做：

for i in list1:
    for x in list2:
        if str(x) == str(i):
            #Do stuff, like add up point
        else:
            #Do stuff, like subtract points, or put in 'pass' for Python to pass the condition

我希望这对您有所帮助。如果您还有更多的海藻，我会为他们开放。

编辑：此代码有效，请尝试了解：

import random
global player_points
player_points = 0

#Winning numbers
def winningNumbers():
  winning_numbers = []
  for i in range(5):
    x = random.randint(1,50)
    winning_numbers.append(x)
  print("Today's winning numbers are: " + str(winning_numbers))
  return winning_numbers

#Get player numbers
def player_numbers(winning_numbers):
  user_input = []
  while len(user_input) < 5:
    number = input("Chose the numbers from 1-50:")
    try:
      number = int(number)
    except ValueError:
      print("That's not a number!")
      continue
    if number in user_input:
      print("You already chosen this number!")
    elif number not in range(1,51):
      print("The number is out of range")
    else:
      user_input.append(number)
  print("Your chosen numbers are: " + str(user_input))
  return user_input
#Compare numbers
def compare_numbers(user_input, winning_numbers):
  global player_points
  for i in winning_numbers:
    for x in user_input:
        if str(x) == str(i):
            player_points = player_points + 1
        else:
            pass
  print(player_points)

#Loop functions
while True:
    compare_numbers(player_numbers(winningNumbers()), winningNumbers())

问候，来自CCD的Chris van den Hoorn

Answer 3

使用

set(user_input_list) & set(generic_list)

以获得两个列表中的通用值。

比较2个列表中的项目

3 个答案: