Question

我已经开发了以下查询，但是无法正常工作：

WITH TABLE1 AS
(
SELECT 613414473 as ID,  1706014200964  as P_NUM, 119539 as d_id,  'F20.0'  AS CODE FROM DUAL UNION ALL
SELECT 613414473 as ID,  1706014200964  as P_NUM, 119539 as d_id,  'F22.0'  AS CODE FROM DUAL UNION ALL
SELECT 613415801 as ID,  1707045167741  as P_NUM, 115182 as d_id,  'A94.0'  AS CODE FROM DUAL UNION ALL
SELECT 613415801 as ID,  1707045167741  as P_NUM, 115182 as d_id,  NULL     AS CODE FROM DUAL UNION ALL
SELECT 613417084 as ID,  1702038456441  as P_NUM, 6541   as d_id,  'E79'    AS CODE FROM DUAL UNION ALL
SELECT 613417084 as ID,  1702038456421  as P_NUM, 6541   as d_id,  'I10'    AS CODE FROM DUAL UNION ALL
SELECT 613418372 as ID,  1706226211517  as P_NUM, 25727  as d_id,  'F32.9'  AS CODE FROM DUAL )
SELECT T1.* 
    , CASE when regexp_like( CODE, 'C0[5-9]|' ||
                               'A0[0-9]|A1[0-9]|A2[0-9]|A3[0-9]|A4[0-9]|A5[0-9]|A6[0-9]|A7[0-9]|A8[0-9]|A9[0-7]|' )
                 THEN 1
                 ELSE 0  END AS FOUND_CODE    
FROM  TABLE1 T1;

我希望将类似C0[5-9]%或A0[0-97]的代码标记为值1，然后如果找到至少一个设置所有标记的代码，则对同一p_num进行标记p_num到1。

以上示例输出：

| 613414473|1706014200964|119539|F20.0|0|
| 613414473|1706014200964|119539|F22.0|0|
| 613415801|1707045167741|115182|A94.0|1|
| 613415801|1707045167741|115182|NULL |1|
| 613417084|1702038456441|6541  |E79  |0|
| 613417084|1702038456421|6541  |I10  |0|
| 613418372|1706226211517|25727 |F32.9|0|

如何修改查询以获取该输出？还有我可以使用的更好的正则表达式吗？

Answer 1

根据您的描述，正则表达式模式应为

'^(C0[5-9]|A[0-8][0-9]|A9[0-7])'

^锚定到值的开头，并且括号允许任何用管道分隔的模式匹配；并简化了模式，因为A00至A89可以一键处理。

这标志着与原始查询相同的单行。下一步是将其移到子查询中，然后使用由p_num分区的解析函数，您希望该函数很常见：

max(found_code) over (partition by p_num)

所以一起变成了（与其他行匹配另一个规则）：

with table1 (id, p_num, d_id, code) as
(
  select 613414470, 1706014200960, 119530, 'D99'   from dual union all
  select 613414471, 1706014200960, 119531, 'C05'   from dual union all
  --
  select 613414473, 1706014200964, 119539, 'F20.0' from dual union all
  select 613414473, 1706014200964, 119539, 'F22.0' from dual union all
  select 613415801, 1707045167741, 115182, 'A94.0' from dual union all
  select 613415801, 1707045167741, 115182, null    from dual union all
  select 613417084, 1702038456441, 6541  , 'E79'   from dual union all
  select 613417084, 1702038456421, 6541  , 'I10'   from dual union all
  select 613418372, 1706226211517, 25727 , 'F32.9' from dual 
)
select id, p_num, d_id, code, max(found_code) over (partition by p_num) as found_code
from (
  select t1.*
       , case when regexp_like( code, '^(C0[5-9]|A[0-8][0-9]|A9[0-7])' )
              then 1
              else 0
         end as found_code
  from table1 t1
);

           ID         P_NUM          D_ID CODE     FOUND_CODE
------------- ------------- ------------- ----- -------------
    613414470 1706014200960        119530 D99               1
    613414471 1706014200960        119531 C05               1
    613414473 1706014200964        119539 F20.0             0
    613414473 1706014200964        119539 F22.0             0
    613415801 1707045167741        115182 A94.0             1
    613415801 1707045167741        115182                   1
    613417084 1702038456441          6541 E79               0
    613417084 1702038456421          6541 I10               0
    613418372 1706226211517         25727 F32.9             0

根据正则表达式设置标志列

1 个答案: