Question

具有此JS文件：

define(["dojo/_base/lang",
    "dojo/dom",
    "dojo/dom-class",
    "dojo/dom-attr",
    "dojo/query",
    "dojo/on",
    "dojo/string",
    "dojo/dom-construct",
    "dojo/sniff",
    "dojo/ready",
    "dojo/Deferred",
    "dijit/registry",
    "caretalks/utils/form/addressForm",
    "caretalks/dialogManager",

    "caretalks/utils/placeholders",
    "caretalks/widget/Button",
    "caretalks/widget/MenuItem",
    "caretalks/widget/form/Select",
    "caretalks/validation/Validator"],

    function(lang, dom, domClass, attr, query, on, string, construct, sniff, ready, Deferred, registry, addressForm, dialogManager,
            placeholders, Button, MenuItem, Select, Validator) {

和此功能：

handleSuccess : function(response) {

    var obj = JSON.parse(response);
    var node = dom.byId("phoneNumber.errors");   <<--- returns null! 

},

和该函数的调用：

var node1 = dom.byId("phoneNumber.errors");   <<--- returns NOT null!

var _self = this;
this.showPropagateChangeDialog(args.propagateChangesDialog, document.forms[args.formName]).then(function(){
    console.info('Posting ' + args.formName + ' to URL: ' + args.url + ' with: ', bindings);
    caretalks.requestManager.ajaxPost(bindings).then(_self.handleSuccess,placeholders.enable);
});

我需要使用div来获得dom.byId()，当我在函数外使用它时，它将返回所需的实际值，但是当它在函数内时，它将返回null。

dom已初始化，并且可以在此处找到byId()，但所需的值是返回undefined。

如何解决此问题？我在这里想念什么？

JavaScript函数范围的问题

0 个答案: