Question

这是我为CS课制作的文字冒险游戏的一小部分。您正在探索一所房子，并通过告诉游戏是否要向北，向南，向东或向西走来导航。
因此，如果您输入了错误的单词（例如Nroth，Suoth，Eas或Weast）之一，则我想添加一些内容来告诉您输入无效的内容。这些只是示例，但希望您理解我的意思，即使它与北，南，东或西不完全匹配。在该部分代码中我该怎么做？

我举了一个错误的例子，如果您在拼写错误中显示“ elif room ==“ porch”，但我想输出该错误，但是即使出现该错误，它也应该继续询问您要去哪个方向因为到目前为止，它继续询问您要去哪个方向，而无论您输入什么内容，它都不会输出根据您输入的房间而应该说的文字。

def pickRoom(direction, room):
    if(direction == "quit") or (direction == "exit"):
        print("Better luck next time!")
        return "Exit"
    elif room == "Porch":
        if direction == "North":
            return "Pantry"
        else:
            print("That is not a valid entry!")
    elif room == "Pantry":
        if direction == "North":
            return "Kitchen"
        elif direction == "East":
            return "DiningRoom"
    elif room == "DiningRoom":
        if direction == "West":
            return "Pantry"
    elif room == "Kitchen":
        if direction == "West":
            return "LivingRoom"
        elif direction == "East":
            return "Bedroom"
    elif room ==  "Bedroom":
        if direction == "West":
            return "Kitchen"
    elif room == "LivingRoom":
        if direction == "West":
            return "Bathroom"
        elif direction == "North":
            return "Stairs"
    elif room == "Bathroom":
        if direction == "East":
            return "LivingRoom"
    elif room == "Stairs":
        if direction == "South":
            return "Bar"
    elif room == "Bar":
        if direction == "East":
            return "Shop"
    elif room == "Shop":
        if direction == "North":
            return "Closet"
        elif direction == "South":
            return "Storage"
    elif room == "Storage":
        if direction == "North":
            return "Shop"
    elif room == "Closet":
        if direction == "South":
            return "Shop"

让我知道您是否需要一大部分代码甚至整个.py文件来找出答案，谢谢。

Answer 1

elif room.lower() in ('perch','peach','pooch'):

您可能只想列出所有要指出的错误拼写。如果他们做出的选择不正确，请检查他们输入的值是否在此列表中。

Answer 2

我不确定您需要什么，但这可能会有所帮助：

directions = ["south", "west", "east", "north"]
while True:
    move = input("Choose which way you would like to go\n")
    if move.lower() in directions:
        print("You have chosen to go " + move)
    else:
        print("Invalid move!")

仅是一个想法，这是一个输出：

>>Choose which way you would like to go
north
>>You have chosen to go north
>>Choose which way you would like to go
North
>>You have chosen to go North
>>Choose which way you would like to go
nothr
>>Invalid move!
>>Choose which way you would like to go

Answer 3

您可以尝试根据正确的选择列表进行测试。我希望这会有所帮助！

if room in roomList:
    # availableDirection is a dictionary that 
    # has rooms as keys and valid directions as values.
    if direction in availableDirection[room]:
        # return the next room from a dictionary representing the 
        # current room where the key is direction and value is the next room.
    else:
        return "Invalid direction"
else:
    return "Invalid room"

Answer 4

要按照要求保留在所示的代码部分内，只需在末尾添加

else:
    print("Sorry, that does not make sense to me.")
    return room

这样，您可以解决当前问题，在没有与输入匹配的已编程选项的情况下，不可预测的值将重新调整为新的当前房间。在这种情况下，通过返回参数room，存储当前房间的变量将继续一个有效房间（当前房间）。

当返回一个不可预测的值时，它很可能不是正确的房间名称之一，为了使逻辑结构保持正确，它需要使用正确的房间名称。一旦room变量包含垃圾，它将再也无法匹配任何选项，因此不再输出任何有意义的信息。

作为防止房间垃圾（由于任何可能的事故之一）的额外预防措施，您可以检查房间是否为现有房间之一，否则将其重置为默认房间-或出现错误消息退出< br /> “糟糕，意外传送到未知空间。下次再见。”

如果输入的输入被视为“无效”，则尝试继续请求输入

4 个答案: