使用C#和foreach从JSON字符串获取第二级值

时间:2018-11-01 08:00:47

标签: c# arrays json.net

完成JSON的新手-这是我第一次使用C#尝试JSON。

我有一条从HTTP get请求返回的记录。

var exchRateData = Get($"https://api.exchangeratesapi.io/2018-10-30?base=EUR&symbols=AUD");

返回:  {"date":"2018-10-30","rates":{"AUD":1.6025},"base":"EUR"}

AUD和1.6025值都是GET请求中的变量。因此,GET请求可以是针对SGD或INR的请求,并在其中返回:

{"date":"2018-10-30","rates":{"SGD":0.0187977737},"base":"INR"}

总是返回带有级别的一条记录,就像上面的两个示例一样。

我要访问的是第二级值

{"AUD":1.6025} or {"SGD":0.0187977737}

我尝试过:

var jsonResult = JsonConvert.DeserializeObject<Dictionary<string, dynamic>>(exchRateData);
                    foreach (var keyValue in jsonResult)
                {
                    try
                    {
                        LblGetValues.Text = LblGetValues.Text + "Key: " + keyValue.Key + " Value:" + keyValue.Value + "<br>";
                        if (keyValue.Key == "date")
                            LblDate.Text = keyValue.Value;

//This is where I get stuck.
                        if (keyValue.Key == "rates")
                        {
// I would like to be able to do this here : 
//string currencyCode =  "AUD" (or "SGD" if second GET request)
//double currencyRate = 1.6025  (or 0.0187977737 if second GET request)
                            //JArray secondLevel = new JArray("rates");

                         //   LblRate.Text = keyValue.Value.ToString();

                        }

                        if (keyValue.Key == "base")
                            LblBase.Text = keyValue.Value;
                    }
                    catch (Exception errMsg)
                    {
                        LblMsg.Text = errMsg.Message + errMsg.StackTrace;
                    }
                }

请帮助。...

3 个答案:

答案 0 :(得分:2)

我建议使用JSON.NET

在这里,您将反序列化JSON字符串到c#模型类中

您的模型类看起来像这样Model Generated using json2csharp

public class Rates
{
    [JsonProperty(PropertyName = "fieldName")]
    public double currency { get; set; }
}

public class RootObject
{
    public string date { get; set; }
    public Rates rates { get; set; }
    public string @base { get; set; }
}

这就是您使用JSON.NET反序列化的方式

// THis works for normal secanario but it won't work for you 
var exchangeRates = JsonConvert.DeserializeObject<RootObject>("Your Json String goes here");
  

但是您的JSON场景有点复杂,因此您必须使用   CustomContractResolver

以下是示例

ContractResolver类

internal class CustomContractResolver : DefaultContractResolver
{
    public CustomContractResolver(string fieldName)
    {
        FieldName = fieldName;
    }

    public string FieldName { get; set; }

    protected override string ResolvePropertyName(string propertyName)
    {
        return propertyName == "fieldName" ? FieldName : base.ResolvePropertyName(propertyName);
    }
}

如何使用此设置

var settings = new JsonSerializerSettings
{
    DefaultValueHandling = DefaultValueHandling.Ignore,
    MissingMemberHandling = MissingMemberHandling.Ignore,
    ContractResolver = new CustomContractResolver("Pass Your currency here")
};

// Make Http Calls here and replace returned string in below method

var data = JsonConvert.DeserializeObject<RootObject>("Your JSON String", setting);
// Here You can access your currency rates
double currencyRate = data.currency;

答案 1 :(得分:1)

   public class Rates
    {
        public double AUD { get; set; }
    }

    public class ObjectCurrency
    {
        public string date { get; set; }
        public Rates rates { get; set; }
        public string @base { get; set; }
    }


  var data= JsonConvert.DeserializeObject<ObjectCurrency>(exchRateData);

答案 2 :(得分:1)

如果只有一个速率(这是OP想要的),则可接受的解决方案可以很好地工作,但不能以超过1个速率的方式工作。另外,它还增加了额外的复杂性,可以通过使用Dictionary来避免(见下文)。

示例-以下请求(AUDUSDGBP

https://api.exchangeratesapi.io/2018-10-30?base=EUR&symbols=AUD,USD,GBP

将返回以下json:

  

{“ date”:“ 2018-10-30”,“ rates”:{“ USD”:1.1372,“ GBP”:0.89148,“ AUD”:1.6025},“ base”:“ EUR”}

您可以使用以下C#类反序列化json字符串:

public class ExchangeRate
{
    [JsonProperty("date")]
    public string Date { get; set; }

    [JsonProperty("rates")]
    public Dictionary<string, decimal> Rate { get; set; }

    [JsonProperty("base")]
    public string Base { get; set; }
}

反序列化json字符串:

string json = @"{""date"":""2018-10-30"",""rates"":{""USD"":1.1372,""GBP"":0.89148,""AUD"":1.6025},""base"":""EUR""}";

ExchangeRate rate = JsonConvert.DeserializeObject<ExchangeRate>(json);

结果:

Deserialized object

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