我具有列类型为varchar(8192) latin2_croatian_ci
的Mysql数据库。我在其中插入这样的文本:Čćžvasfamižsafaš
(这是带有特殊字符的随机文本)。当我在mysql中预览数据时,它确实具有该特殊字符(没有被?
或其他替换)。
我有php
页
<!DOCTYPE html>
<?php
session_start();
include("somePhpFile");
$cid = $mysqli->escape_string($_GET["id"]);
$sql = "SELECT BODY FROM ... WHERE CLANAKID = '$cid'";
if($result = $mysqli->query($sql))
{
$clanak = mysqli_fetch_assoc($result);
$body = $clanak["BODY"];
}
?>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Some title</title>
<link rel="stylesheet" type="text/css" href="../Styles/Clanak.css?id=4" />
<link rel="stylesheet" type="text/css" href="../Styles/DefaultBody.css" />
<meta charset="UTF-8"/>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-2">
<meta http-equiv="Content-Type" content="text/html; charset=windows-1250">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="../jQuery/Header.js"></script>
</head>
<body>
<?php include("someHeaderphp");?>
<div id="BodyDiv">
<?php echo($body); ?>
</div>
</body>
</html>
当我在页面内回显它时,所有特殊字符都将替换为?
和其他字符。我该怎么办?
这是我的Show create table
:
CREATE TABLE `CLANAK` (
`CLANAKID` int(11) NOT NULL AUTO_INCREMENT,
`NASLOV` varchar(64) NOT NULL,
`BODY` varchar(8192) CHARACTER SET latin2 COLLATE latin2_croatian_ci NOT NULL,
`THUMBNAIL` varchar(1024) NOT NULL,
`AKTIVAN` int(11) NOT NULL DEFAULT '1',
PRIMARY KEY (`CLANAKID`)
) ENGINE=MyISAM AUTO_INCREMENT=7 DEFAULT CHARSET=latin1
答案 0 :(得分:0)
首先,让我们进行一些调试。
请提供SHOW CREATE TABLE
和
让我们看一下SELECT col, HEX(col) ...
来丢弃进表的东西。对于Čćžvasfamižsafaš
,十六进制将为
3F3F3F76617366616D693F736166613F (???vasfami?safa?) - the text was messed up when storing.
C8E6BE76617366616D69BE73616661B9 - if it stored correctly into a latin2 column
C48CC487C5BE76617366616D69C5BE73616661C5A1 - correctly stored into utf8 (or utf8mb4)
Trouble with UTF-8 characters; what I see is not what I stored