Question

我大约有100个文件夹，每个文件夹中应读取和分析的文件。

我可以从子文件夹中读取文件，但是我想从以下位置开始处理：第10个文件夹，直到结尾。而且我需要确切的文件夹路径。

我该怎么做？

为澄清我的问题，我从代码中提取了一个示例：

rootDir = 'D:/PhD/result/Pyradiomic_input/'
for (path, subdirs, files) in os.walk(rootDir):        
    sizefile=len(path)
    if "TCGA-" in path :
        print(path)

输出为：

D:/PhD/result/Pyradiomic_input/TCGA-02-0006
D:/PhD/result/Pyradiomic_input/TCGA-02-0009
D:/PhD/result/Pyradiomic_input/TCGA-02-0011
D:/PhD/result/Pyradiomic_input/TCGA-02-0027
D:/PhD/result/Pyradiomic_input/TCGA-02-0046
D:/PhD/result/Pyradiomic_input/TCGA-02-0069

现在我的问题是如何从例如D:/PhD/result/Pyradiomic_input/TCGA-02-0046直到结束，而不是从头开始？我尝试了一些想法，但是没有用。

Answer 1

您可以设置一个标记，以在命中特定目录时捕获

rootDir = 'D:/PhD/result/Pyradiomic_input/'
first_folder = 'TCGA-02-0046'

process = False
for (path, subdirs, files) in os.walk(rootDir):        
    sizefile=len(path)
    if "TCGA-" in path :
        print(path)

        if first_folder in path:
            process = True

        if process:
            #process folder

如果您想要特定的文件夹来指示脚本应停止处理

rootDir = 'D:/PhD/result/Pyradiomic_input/'
first_folder = 'TCGA-02-0046'
last_folder = 'TCGA-02-0099'

process = False
for (path, subdirs, files) in os.walk(rootDir):        
    sizefile=len(path)
    if "TCGA-" in path :
        print(path)

        if first_folder in path:
            process = True

        if last_folder in path:
            break

        if process:
            #process folder

您还可以设置要处理的目录列表

rootDir = 'D:/PhD/result/Pyradiomic_input/'
process_dirs = ['TCGA-02-0046', ...]

process = False
for (path, subdirs, files) in os.walk(rootDir):        
    sizefile=len(path)
    if "TCGA-" in path :
        print(path)

        if any(d in path for d in process_dirs):
            #process folder

Answer 2

您可以简单地跳过不需要的值。这里有些简化：

counter = 0

# mocking the file operations
for path in ["/dir-1", "/dir-2", "/dir-3", "/dir-4", "/dir-5"]:
  # skip the first two paths
  if counter < 2:
    counter += 1
    continue

  # do something    
  print(path)

或者，您可以先收集路径，如下所示：

paths = []

# mocking the file operations
for path in ["/dir-1", "/dir-2", "/dir-3", "/dir-4", "/dir-5"]:
  # collect paths in array
  paths.append(path)

# skip the first two elements
paths = paths[2:]

for path in paths:
  # do something
  print(path)

如果使用生成器表达式，第二个版本可能会短一些，但我更喜欢可读性。

如何提取子文件夹路径？

2 个答案: