Question

我有以下代码，打印出两个日期之间的差异：

print_r((new DateTime('2018-01-01'))->diff(new DateTime('2018-11-01')));

print_r((new DateTime('2018-10-01'))->diff(new DateTime('2018-11-01')));

输出：

DateInterval Object
(
    [y] => 0
    [m] => 10
    [d] => 0
    [h] => 0
    [i] => 0
    [s] => 0
    [f] => 0
    [weekday] => 0
    [weekday_behavior] => 0
    [first_last_day_of] => 0
    [invert] => 0
    [days] => 304
    [special_type] => 0
    [special_amount] => 0
    [have_weekday_relative] => 0
    [have_special_relative] => 0
)
DateInterval Object
(
    [y] => 0
    [m] => 1
    [d] => 1
    [h] => 0
    [i] => 0
    [s] => 0
    [f] => 0
    [weekday] => 0
    [weekday_behavior] => 0
    [first_last_day_of] => 0
    [invert] => 0
    [days] => 31
    [special_type] => 0
    [special_amount] => 0
    [have_weekday_relative] => 0
    [have_special_relative] => 0
)

如您所见，第一个日期差正确返回10个月零天。但是，第二个错误而不是1个月零0天返回，而是错误地返回1个月零1天。

是什么原因造成的？

让我感到困惑的是，我试图在两个PHP沙箱站点上运行此代码，但结果却不一致：

我自己的服务器和https://wtools.io/php-sandbox返回第二天的错误天数。但是例如，http://sandbox.onlinephpfunctions.com/在第二个日期差中正确返回0天。

Answer 1

这是因为服务器时区。只需将所有内容设置为UTC，就可以了。

print_r((new DateTime('2018-10-01', new DateTimeZone('UTC')))->diff(new DateTime('2018-11-01', new DateTimeZone('UTC'))));

https://3v4l.org/PWKiD

没有时区，这确实是意外值。 https://3v4l.org/6v0XI

PHP DateTime差返回错误的天数

1 个答案: