Question

我从这样的数据库中获得了字符串：

$string1 = "1219.56.C38-.C382                 Codex Azcatitlan";
$string2 = "1219.56.C45-.C452                      Codex Cempoallan";

我如何将它们分为：

["1219.56.C38-.C382", "Codex Azcatitlan"]
["1219.56.C45-.C452", "Codex Cempoallan"]

请注意，如果我使用$ stringar1 = explode（“”，$ string1）等。我会得到这个：

array(3)
(
    [0] => string "1219.56.C38-.C382"
    [1] => string "Codex"
    [2] => string "Azcatitlan"
)

等

我需要“法典阿兹卡蒂特兰”

我事先不知道左右元素之间有多少个空格。但是，我们可以假定它将始终大于1个空间。

Answer 1

使用explode()的组合来限制第三个参数为array_map()的零件数，以删除多余的空格：

// this means you will have 2 items and all other spaces 
// after first one  will not be used for `explod`ing
$r = array_map('trim', explode(" ", $string1, 2));

Answer 2

使用preg_split并检查至少2个空格字符。

$string1 = "1219.56.C38-.C382                 Codex Azcatitlan";
$string2 = "1219.56.C45-.C452                      Codex Cempoallan";
print_r(preg_split('/\h{2,}/', $string1));
print_r(preg_split('/\h{2,}/', $string2));

https://3v4l.org/oWbIf

如果$string也应换行，请将\h更改为\s。 \h是水平空白（制表符或空格），\s是任何空白。

{}在正则表达式中创建一个范围。内部的单个值是允许的字符数，内部的,表示最小和最大范围。 2是最小值，并且没有第二个值表示任意数量的其他匹配项。这与+相同，但必须有两个，而不是一个匹配。

Answer 3

您可以结合使用explode()和substr()

$string1 = "1219.56.C38-.C382                 Codex Azcatitlan";

// explode() on spaces
$explode = explode( ' ', trim( $string1 ) ); // apply trim() just in case there are ever leading spaces

$result = array(
    $explode[ 0 ], // give me everything before the first space char
    trim( substr( $string1, strlen( $explode[ 0 ] ) ) ) // give me everything starting from the first space char and apply trim()
);

var_dump( $result );

输出：

array(2) {
  [0]=>
  string(17) "1219.56.C38-.C382"
  [1]=>
  string(16) "Codex Azcatitlan"
}

Answer 4

您可以结合使用const styles = theme => ({ root: { flexGrow: 1, width: "100%", backgroundColor: theme.palette.background.paper }, tabsIndicator: { backgroundColor: "red", textTransform: "capitalize" }, tabRoot: { "&:hover": { color: "red", opacity: 1, textTransform: "capitalize" }, "&$tabSelected": { color: "red", fontWeight: theme.typography.fontWeightMedium, textTransform: "capitalize" }, "&:focus": { color: "red", textTransform: "capitalize" } }, tabSelected: {} });，explode()和array_shift()

implode()

输出：

$string1 = "1219.56.C38-.C382                 Codex Azcatitlan";

// explode() on spaces
$explode = explode( ' ', trim( $string1 ) ); // apply trim() just in case there are ever leading spaces

$result = array(
    array_shift( $explode ), // remove the first element from the array and give me it's value
    trim( implode( ' ', $explode ) ) // $explode has it's first element removed so we can just implode it
);

var_dump( $result );

Answer 5

preg_match_all('~^[a-zA-Z0-9-]+\.[a-zA-Z0-9-]+\.[a-zA-Z0-9-]+\.[a-zA-Z0-9]+\s+([a-zA-Z0-9\s]+)~i', '1219.56.C38-.C382                 Codex Azcatitlan', $matches);

print_r($matches);



Array
(
    [0] => Array
        (
            [0] => 1219.56.C38-.C382                 Codex Azcatitlan
        )

[1] => Array
    (
        [0] => Codex Azcatitlan
    )

）

PHP爆炸多个空间

5 个答案: