Question

如果有一个能射击的小机器人，我正在尝试制作一个游戏。问题在于它仅在不移动时，在向左或向右移动或跳跃时才拍摄。当我按下其他键时，可以做些什么让我的Barspace键起作用吗？我试图将另一个if关键语句放在已经存在但不起作用的关键语句中，就像这样：

elif keys[py.K_LEFT] and man.x >= 0:
    man.x -= man.vel
    man.right = False
    man.left = True
    man.standing = False
    man.idlecount = 0
    man.direction = -1

    if keys [py.K_SPACE] and shootloop == 0:
        if man.left:
            facing = -1

        elif man.right:
            facing = 1

        if len(bullets) < 5:
            man.standing = True
            man.shooting = True
            bullets.append(bulletss(round(man.x + man.lenght//2), round(man.y + man.lenght//2), facing))

        shootloop = 1

我将github留在这里，因此您可以运行该程序。谢谢您的帮助，对不起我的代码。

https://github.com/20nicolas/Game.git

Answer 1

if keys [py.K_SPACE] and shootloop == 0:语句不应放在elif keys[py.K_LEFT] and man.x >= 0:子句中，否则只能在按向左箭头键时射击。

另外，在您的回购中，实际上是

if keys[py.K_RIGHT] and man.x <= 700:
    # ...
elif keys[py.K_LEFT] and man.x >= 0:
    # ...       
elif keys [py.K_SPACE] and shootloop == 0:

这意味着仅在未按下K_LEFT和K_RIGHT的情况下才会执行该命令，因为这些语句的顺序相同。if ... elif。 / p>

此版本对我有用：

elif keys[py.K_LEFT] and man.x >= 0:
    man.x -= man.vel
    man.right = False
    man.left = True
    man.standing = False
    man.idlecount = 0
    man.direction = -1
else:
    man.standing = True

if keys [py.K_SPACE] and shootloop == 0:
    if man.left:
        facing = -1

    elif man.right:
        facing = 1

    if len(bullets) < 5:
        man.standing = True
        man.shooting = True
        bullets.append(bulletss(round(man.x + man.lenght//2), round(man.y + man.lenght//2), 1))

    shootloop = 1
else:
    man.shooting = False

多个按键按Pygame

1 个答案: