Question

我有以下问题：

我有一个字典列表，想遍历列表（ temp_list ）并检查：

如果 temp [x] 和 temp [y] 的值 dic [“ z”] 位于 distance_value 。
如果不是，请在 temp [x] 和 temp [y] 之间插入一个新字典，其中包含 z_value （< > temp [y] -temp [x]）/ 2 ），将其命名为 dic_x_y
然后填充新插入的dic（ dic_x_y [“ t1”] ， dic_x_y [“ angle1”] 和 dic_x_y [“ material “] ），而dic的值以 temp [x]

以下是带有列表和变量的数据：

    distance_value = 1000

    temp = [
    {
      "z": 1450,
      "t1": 0,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 1950,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 12800,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 13000,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 25900,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 26000,
      "t1": 10,
      "angle1": 90,
      "material": "Balsa 150"
    }]

我搜索了很多问题，但是找不到答案。我希望我能清楚地说明我的问题，有人可以帮助我。提前谢谢。

我真的不知道如何开始，但是那是我的想法，我无法上班：

distance_value = 1000

for dic in temp: 
if "dic["z"] +1 (second element of the list) - dic["z"] < distance_value:
    new_dic = {"z": (dic["z"]+1 - dic["z"]), "t1": dic["t1"] , "angle1":dic["angle1"], "material":dic["material"] }
    temp.insert[dic["z"]+1, new_dic]

Answer 1

来自我的 json 测试文件test.json：

[
    {
      "z": 1450,
      "t1": 0,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 1950,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 12800,
      "t1": 25,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 13000,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 25900,
      "t1": 15,
      "angle1": 90,
      "material": "Balsa 150"
    },
    {
      "z": 26000,
      "t1": 10,
      "angle1": 90,
      "material": "Balsa 150"
    }]

python 代码：

import json
with open('test.json') as f:
    temp = json.load(f)
distance_value = 1000

temp.sort(key=lambda k: k['z'])
counter = 0
Continue = True
while (Continue):
    for i in range (0,len(temp)-1):
        if(temp[i+1]['z'] - temp[i]['z'] > distance_value):
            Continue = True
            new_dic = {"z": (temp[i+1]['z'] + temp[i]['z'])/2., "t1": temp[i]['t1'], "angle1": 90, "material": temp[i]['material']}
            temp.append(new_dic)
            temp.sort(key=lambda k: k['z'])
            break
        else:
            Continue = False

temp_as_string = json.dumps(temp, sort_keys=True, indent=4, separators=(',', ': '))
print(temp_as_string)

我的输出：

[
    [
{
    "z": 1450,
    "t1": 0,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 1950,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 2628.125,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 3306.25,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 3984.375,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 4662.5,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 5340.625,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 6018.75,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 6696.875,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 7375.0,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 8053.125,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 8731.25,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 9409.375,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 10087.5,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 10765.625,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 11443.75,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 12121.875,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 12800,
    "t1": 25,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 13000,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 13806.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 14612.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 15418.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 16225.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 17031.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 17837.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 18643.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 19450.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 20256.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 21062.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 21868.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 22675.0,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 23481.25,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 24287.5,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 25093.75,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 25900,
    "t1": 15,
    "angle1": 90,
    "material": "Balsa 150"
},
{
    "z": 26000,
    "t1": 10,
    "angle1": 90,
    "material": "Balsa 150"
}
]
[Finished in 0.096s]

逻辑如下：

在有条件的情况下运行while循环，我应该继续遍历字典并检查吗？ ： Continue
在while循环中，循环遍历当前列表项，检查是否有任何可能的list [i + 1] ['z']-list [i] ['z']大于设置的距离（这是检查循环）
如果找到，则使用中间点Z值制作一个新字典，追加并重新排序（这很重要），然后通过断开{{1}，从for循环中断（从第一次出现时从检查循环中断）。 } while循环的条件仍然为真
在while循环的稍后阶段，当我们遍历所有for循环并检查未找到条件时，则Continue为假，而while循环中断

检查dic列表并添加值

1 个答案: