Question

这是我的代码：

//Models definition
var User = sequelize.define('user', ...);
var Address = sequelize.define('address', ...);
var Club = sequelize.define('club', ...);
//Club scopes
  scopes: {
    withUser: {
      include: [
        { model: User }
      ]
    },

//Models associations
User.hasOne(Address);
Club.hasOne(User);
Club.hasOne(Address);



//Main

//Create address
  var addressToCreate = {};
  if(body.address) addressToCreate.address = body.address;
  if(body.city) addressToCreate.city = body.city;
  if(body.zipCode) addressToCreate.zipCode = body.zipCode;

//Get user from db
  var user = await User.findByPk(body.user);


  var clubToCreate = { name: body.name, phone: body.phone };

//Persist Address in db
  return Address.create(addressToCreate)
  .then(address => {

//Persist club in db
    return Club.create(clubToCreate)
    .then(club => {

//Associate User and Address to Club
      club.setAddress(address);
      club.setUser(user);

//Save club with associated models
      return club.save()
    })
    .then(club => Club.scope('withUser').findByPk(club.id))
    .then(club => { console.log(club); return club; })
  })

在我的数据库中，表地址包含userId和clubId，表用户包含clubId;

此代码似乎可以用于创建和关联模型。但是console.log显示的最终俱乐部显示用户：null

但是，在db中，表用户中有好行，并且具有引用俱乐部ID的好外键

我的日志显示，选择请求（来自Club.findByPk）在更新之前完成（来自club.save）。就像.then在兑现承诺之前执行

抱歉我的英语不好，希望有人能帮忙

Answer 1

您正在使用async/await，但会根据获取用户的代码将其与旧的promise样式混合使用。以下是async/await样式的代码副本，尽管您可能不需要重新获取club对象，依此类推，所以继续进行调试。

const address = await Address.create(addressToCreate);
let club = await Club.create(clubToCreate);
console.log('created club', club);

club.setAddress(address);
club.setUser(user);
await club.save();
console.log('saved club', club);

club = await Club.scope('withUser').findByPk(club.id);
console.log('reloaded club', club);
return club;

在save（）完成之前对回调进行排序

1 个答案: