我习惯通过单击远程服务器在推送时打印的链接来创建合并请求(MR):
╰─ git push
Counting objects: 33, done.
Delta compression using up to 4 threads.
Compressing objects: 100% (33/33), done.
Writing objects: 100% (33/33), 3.46 KiB | 1.73 MiB/s, done.
Total 33 (delta 31), reused 0 (delta 0)
remote:
remote: To create a merge request for modelref, visit:
remote: https://gitlab.com/foo/bar/merge_requests/new?merge_request%5Bsource_branch%5D=mybranch
问题是MR的目标分支将设置为预先配置的master
分支*
因此,基本上,我希望将一个merge_request%5Btarget_branch%5D=
URL参数设置为父分支的URL(this script找到它)。
我可以编写一个本地pre-push
钩子(因为不存在本地post-push
操作),该钩子可以代替我单击该URL,但是您能找到一个不太丑陋的hack吗?
* ,如果我不立即更改目标分支,则会浪费时间,因为更改此表单字段会重置所有其他字段(https://gitlab.com/gitlab-org/gitlab-ce/issues/22090)
答案 0 :(得分:1)
这就是我最终要做的事情:
〜/ bin / git-branchestor.sh
#!/bin/bash
# Find closest ancestor given two candidate branches
branch=`git rev-parse --abbrev-ref HEAD`
commit1=`git merge-base $branch ${1}`
commit2=`git merge-base $branch ${2}`
ancestor=`git merge-base ${commit1} ${commit2}`
if [[ "$commit1" == "$ancestor" ]]; then
echo ${2}
else
echo ${1}
fi
我的功能分支从hotfix
或develop
分支出来,这些是我在git-branchestor.sh
脚本中提供的参数:
.git / hooks / pre-push
#!/bin/bash
remote="$1"
url="$2"
z40=0000000000000000000000000000000000000000
while read local_ref local_sha remote_ref remote_sha
do
if [ "$local_sha" = $z40 ]
then
# Handle delete
:
else
if [ "$remote_sha" = $z40 ]
then
# New branch, examine all commits
range="$local_sha"
else
# Update to existing branch, examine new commits
range="$remote_sha..$local_sha"
fi
branch=$(git rev-parse --abbrev-ref HEAD)
if [[ "$branch" != "hotfix" && "$branch" != "master" && "$branch" != "develop" ]]; then
ancestor=`~/bin/git-branchestor.sh hotfix develop`
echo "Open MR: https://gitlab.com/user/project/merge_requests/new?merge_request%5Bsource_branch%5D=${branch}&merge_request%5Btarget_branch%5D=${ancestor}"
echo ""
fi
fi
done
exit 0