Question

我不确定为什么此代码无法正常工作。我有错误TypeError：'int'对象不可迭代。我需要代码来检查两个不同列表中的用户名和密码，如果用户名和密码与列表中的点匹配并且正确，则用户为“授予访问权限。”

#Part 1: Opening the files and grabbing data
filename1 = "c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\usernames.txt"
file = open(filename1, "r")

#Usernames
users = file.read()
usernameslist = [line.strip() for line in open("c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\usernames.txt")]
print(users)                #Check file
print(usernameslist)       #Check usernames list

filename2 = "c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\passwords.txt"
file = open(filename2, "r")

#Passwords
passwords = file.read()
passwordslist = [line.strip() for line in open("c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\passwords.txt")]
print(passwords)            #Check file
print(passwordslist)       #Check passwords list

#Compile the usernames and passwords lists for easy checking
compiled_list = list(zip(usernameslist,passwordslist))
print(compiled_list)

#Scores
filename3 = "c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\scores.txt"
file = open(filename3, "r")

scores = file.read()
scoreslist = [line.strip() for line in open("c:\\Users\\Anna Hamelin\\Documents\\Python Scripts\\SourceCode\\Project2\\scores.txt")]
print(scores)           #Check file
print(scoreslist)       #Check scores

def login():
    username = input("Please enter your username: ")
    password = input("Please enter your password: ")  
    for i in range(len(usernameslist)):
        if username == i and password == [i]:
            print("Access granted!")
        else:
            print("Incorrect Login credentials, please try again.")


login()

Answer 1

问题出在login()中，您正在使用i作为其内部的迭代器。

def login():
    username = input("Please enter your username: ")
    password = input("Please enter your password: ")  
    for i in [usernameslist]:
        if username == [i]:
            for j in [passwordslist]:
                if password == [j]:
                    return "Access granted!"
                else:
                    return "Incorrect Login credentials, please try again."
        else:
            return "Incorrect Login credentials, please try again."

以上内容应找到密码并与您的逻辑配合使用。但是，您是否不应该使用特定的用户名作为密码？这是在检查用户名和密码是否可用，而不是密码是否与用户名匹配。当您分别遍历浏览密码和用户名时，您只需检查某人是否具有密码和某人是否具有用户名（是否是同一个人）。如果是这样，请替换为：

def login():
    username = input("Please enter your username: ")
    password = input("Please enter your password: ")  
    for i in range(len(usernameslist)):
        if username == i and password == j:
            return "Access granted!"
        else:
            return "Incorrect Login credentials, please try again."

请确保在两个列表中用户名和密码的顺序相同。或者，我建议存储如下所示的 2D列表：

list = [["Annie","password1"],["bob","wordpass39"]]，其中第一项是用户名，第二项是密码。

编辑：，使用固定的login()功能，您现在应该这样做：

def login():
    username = input("Please enter your username: ")
    password = input("Please enter your password: ")  
    for i in range(len(usernameslist)):
        if username == i and password == i:
            print("Access granted!")
        else:
            print("Incorrect Login credentials, please try again.")

使用列表检查用户名和密码

1 个答案: