如何遍历对象数组并使用特定的对象属性javascript输出数组

Question

var obo = [{
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }, {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }, {
        "parcelId": "009",
        "userid": "tomi",
        "location": "kwara"
    }
]

我想遍历并返回数组。我已经试过剪接了，没用

var obo = [{
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "userid": "tomi",
        "location": "kwara"
    },
    {
        "userid": "tomi",
        "location": "kwara"
    }
]

正在尝试填充数组，以免其中没有parcelid

Answer 1

您可以将.map()用于某些对象分解：

var data = [
  {"parcelId": "009", "userid": "tomi", "location": "kwara"},
  {"parcelId": "009", "userid": "tomi", "location": "kwara"},
  {"parcelId": "009", "userid": "tomi", "location": "kwara"}
];

var result = data.map(({userid, location, ...rest}) => ({userid, location}));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

参考：

• Array.prototype.map()
• Object Destructuring

Answer 2

您需要使用.map()

obo = obo.map(function(item){
  return {
    userid: item.userid,
    location: item.location
  };
});

var obo = [
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  }
];

obo = obo.map(function(item){
  return {
    userid: item.userid,
    location: item.location
  };
});
console.log(obo);

Answer 3

Array.prototype.map()呢？

var obo = [{
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  },
  {
    "parcelId": "009",
    "userid": "tomi",
    "location": "kwara"
  }
]

var expected = [];

obo.map((elm, ind) => {
  expected.push({
    "userid": elm.userid,
    "location": elm.location
  })
})
console.log(expected)

Answer 4

您可以尝试这样的事情

obo = obo.map(el => {
  let obj = {
    userid: el.userid,
    location: el.location
  };
  return obj;
});

或者对于一个班轮，您可以这样做

obo = obo.map(({userid,location})=>({userid,location})));