Question

我在解决将数组合并到多维数组方面遇到麻烦。

我的数组如下：

Array
(
    [0] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_Sinoskysun International (HK) CO., LTD
        )

    [1] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_RUTRONIK Elektronische Ba
        )

    [2] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_TTI
        )

    [3] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_ARROW CENTRAL EUROPE GMBH
        )

    [4] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_TDK
        )

    [5] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_YANGZHIDING ELECTRONICS
        )
     [6] => Array
        (
            [id] => 41301
            [regNumber] => P+CSM-302.01
            [name] => 100n SMD 0603 5% X7R 25V
            [madeBy2] => 
        )
     [7] => Array
        (
            [id] => 24526
            [regNumber] => P+CSM-097.04
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_TDK
        )
)

我需要像这样合并它们：

Array
(
    [0] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Array
            (
                "Pro_Sinoskysun International (HK) CO., LTD",
                "Pro_RUTRONIK Elektronische Ba",
                "Pro_TTI",
                "Pro_ARROW CENTRAL EUROPE GMBH",
                "Pro_TDK",
                "Pro_YANGZHIDING ELECTRONICS"
            )
       )
     [1] => Array
        (
            [id] => 41301
            [regNumber] => P+CSM-302.01
            [name] => 100n SMD 0603 5% X7R 25V
            [madeBy2] => 
        )
     [2] => Array
        (
            [id] => 24526
            [regNumber] => P+CSM-097.04
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_TDK
        )
)

输入数组可以是5或500个项目，我需要通过ID进行合并。.彼此之间只有一件事不同，它是由谁制造的。有可能吗？

如果需要更多，我可以添加。：）

非常感谢您的帮助。

Answer 1

此代码将产生所需的输出，而不管数组是否具有不同的id值。此代码确实假定所有相似的产品均按顺序分组：

$output = array();
$i = -1;
foreach ($array as $arr) {
    if ($i < 0 || $output[$i]['id'] != $arr['id'] || $output[$i]['regNumber'] != $arr['regNumber'] || $output[$i]['name'] != $arr['name']) {
        // new product
        $output[++$i] = $arr;
        $output[$i]['madeBy2'] = array($arr['madeBy2']);
    }
    else {
        // same product, new manufacturer
        $output[$i]['madeBy2'][] = $arr['madeBy2'];
    }
}
print_r($output);

Demo on 3v4l.org

备用版本：如果有多个值，则仅将madeBy2元素放入数组：

$output = array();
$i = -1;
foreach ($array as $arr) {
    if ($i < 0 || $output[$i]['id'] != $arr['id'] || $output[$i]['regNumber'] != $arr['regNumber'] || $output[$i]['name'] != $arr['name']) {
        // new product
        $output[++$i] = $arr;
    }
    else {
        // same product, new manufacturer
        if (!is_array($output[$i]['madeBy2'])) 
            $output[$i]['madeBy2'] = array($output[$i]['madeBy2'], $arr['madeBy2']);
        else
            $output[$i]['madeBy2'][] = $arr['madeBy2'];
    }
}
print_r($output);

输出（用于示例数据）

Array
(
    [0] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Array
            (
                "Pro_Sinoskysun International (HK) CO., LTD",
                "Pro_RUTRONIK Elektronische Ba",
                "Pro_TTI",
                "Pro_ARROW CENTRAL EUROPE GMBH",
                "Pro_TDK",
                "Pro_YANGZHIDING ELECTRONICS"
            )
       )
     [1] => Array
        (
            [id] => 41301
            [regNumber] => P+CSM-302.01
            [name] => 100n SMD 0603 5% X7R 25V
            [madeBy2] => 
        )
     [2] => Array
        (
            [id] => 24526
            [regNumber] => P+CSM-097.04
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Pro_TDK
        )
)

Demo on 3v4l.org

Answer 2

我建立了一个数组，该数组由数据中的id值索引，如果尚未设置，那么我将用数据创建一个新元素-尽管madeBy2被创建为数组。如果元素已经存在，则将新值添加到现有值列表中（使用[]）...

$out = [];
foreach ( $inp as $data )   {
    if ( isset ($out[$data['id']])) {
        $out[$data['id']]["madeBy2"][] = $data["madeBy2"];
    }
    else {
        $out[$data['id']] = [ "id"=>$data['id'],
            "regNumber" => $data['regNumber'],
            "name" => $data['name'],
            "madeBy2" => [$data['madeBy2']]];
    }
}
print_r(array_values($out));

这将留下一个由id索引的数组，因此我在array_values()中使用print_r()，可以根据需要将其保留。

Answer 3

代码注释

foreach ($array as $arr) {
    if(!isset($output[$arr["id"]])){ // if item does not exist
        $output[$arr["id"]] = $arr; // create array
        $output[$arr["id"]]['madeBy2'] = [$output[$arr["id"]]['madeBy2']]; // change type on madeBy2 to array
    }else{    
        $output[$arr["id"]]['madeBy2'][] = $arr['madeBy2']; // it item exist add madeBy2 to the list
    }
}
$output = array_values($output); // remove associative array keys.
print_r($output);

此方法不依赖于要排序的列表，只有madeBy2是硬编码。
意味着如果一个数组中有一个额外的项目，则此方法将使其与Nigel的项目相反。
输出：

Array
(
    [0] => Array
        (
            [id] => 41844
            [regNumber] => CSM-057.05
            [name] => 100nSMD060310%X7R25V
            [madeBy2] => Array
                (
                    [0] => Pro_SinoskysunInternational(HK) CO.,LTD
                    [1] => Pro_RUTRONIKElektronischeBa
                    [2] => Pro_TTI
                    [3] => Pro_ARROWCENTRALEUROPEGMBH
                    [4] => Pro_TDK
                    [5] => Pro_YANGZHIDINGELECTRONICS
                )

        )

    [1] => Array
        (
            [id] => 41301
            [regNumber] => P+CSM-302.01
            [name] => 100n SMD 0603 5% X7R 25V
            [madeBy2] => Array
                (
                    [0] => 
                )

        )

    [2] => Array
        (
            [id] => 24526
            [regNumber] => P+CSM-097.04
            [name] => 100n SMD 0603 10% X7R 25V
            [madeBy2] => Array
                (
                    [0] => Pro_TDK
                )

        )

)

https://3v4l.org/iCjk1

带有额外项目的演示：
https://3v4l.org/0jmpL

通过键将数组合并为多维

3 个答案: