Question

我想将结构作为参数传递给函数。但是我编译时失败了。这是我的结构定义。它在svm.h中定义，并在svm.cpp中声明

#ifdef __cplusplus
extern "C" {
#endif
struct svm_model
{
    struct svm_parameter param; /* parameter */
    int nr_class;       /* number of classes, = 2 in regression/one class 
    svm */
    int l;          /* total #SV */
    struct svm_node **SV;       /* SVs (SV[l]) */
    double **sv_coef;   /* coefficients for SVs in decision functions 
    (sv_coef[k-1][l]) */
    double *rho;        /* constants in decision functions (rho[k*(k-1)/2]) 
    */
    double *probA;      /* pariwise probability information */
    double *probB;
    int *sv_indices;        /* sv_indices[0,...,nSV-1] are values in 
    [1,...,num_traning_data] to indicate SVs in the training set */

                            /* for classification only */

    int *label;     /* label of each class (label[k]) */
    int *nSV;       /* number of SVs for each class (nSV[k]) */
                    /* nSV[0] + nSV[1] + ... + nSV[k-1] = l */
                    /* XXX */
    int free_sv;        /* 1 if svm_model is created by svm_load_model*/
                        /* 0 if svm_model is created by svm_train */
};
....
#ifdef __cplusplus
}
#endif

这是我的函数定义。它在syll_fragmentation.h中声明，并在syll_fragmentation.c中定义声明：

 void real_time_predict(struct svm_model *model, SAMPLE *sum_normal);

定义：

 void real_time_predict(struct svm_model *model, SAMPLE *sum_normal) {}

在主函数中，我将此函数称为：

 struct svm_model *model;
 if ((model = svm_load_model(model_path)) == 0) {
        fprintf(stderr, "cant load model file \n");
        exit(1);
 }

 SAMPLE *sum_normal = (SAMPLE*)malloc(sizeof(SAMPLE) * 91);
 mfcc_load_normalized_sum(sum_normal, sum_path);
 real_time_predict(model, sum_normal);

我得到的错误是无效的初始化器，该初始化器使用real_time_predict函数进行引用。我正在使用gcc进行编译。这是错误日志：

syll_fragmentation.c:217:13: error: invalid initializer

第217行是real_time_predict函数的声明。我不知道为什么，请帮助我，谢谢大家！

结构指针函数中的初始化器无效

0 个答案: