AWS |模块中的语法错误:语法无效

时间:2018-11-20 14:35:05

标签: python python-2.7 stomp amazon-mq

我创建了python脚本,该脚本以zip文件的形式上传到AWS Lambda函数中,其中捆绑了Stompy库。

python 2.7的日志:-

Response:
null

Request ID:
"c334839f-ee46-11e8-8970-612f1dc92e41"

Function Logs:
START RequestId: c334839f-ee46-11e8-8970-612f1dc92e41 Version: $LATEST
CONNECTION Started
CONNECTION established
CONNECTION Subscribed
[WARNING]   2018-11-22T11:07:12.798Z    c334839f-ee46-11e8-8970-612f1dc92e41    Unknown response frame type: '' (frame length was 3)
END RequestId: c334839f-ee46-11e8-8970-612f1dc92e41
REPORT RequestId: c334839f-ee46-11e8-8970-612f1dc92e41  Duration: 10027.75 ms   Billed Duration: 10100 ms   Memory Size: 128 MB Max Memory Used: 30 MB

我的代码:-

import time
import boto3
import stomp

kinesis_client = boto3.client('kinesis')


class Listener(stomp.ConnectionListener):
    msg_list = []
    def on_error(self, headers, message):
        print('received an error "%s"' % message)

    def on_message(self, headers, message):
        print('received a message "%s"' % message)
        kinesis_client.put_record(
            StreamName='Purchasing',
            Data=u'{}\r\n'.format(message).encode('utf-8'),
            PartitionKey='0'
        )


def lambda_handler(event, context):
    conn = stomp.Connection(host_and_ports=[('b-4714-4441-8166-47aae158281a-1.mq.eu-central-1.amazonaws.com', 8162)])
    lst = Listener()
    conn.set_listener('Listener', Listener())
    conn.start()
    conn.connect(login='test_mq', passcode='test_mq')
    conn.subscribe(destination='/queue/Purchasing', id='b-4714-4441-8166-47aae158281a', ack='auto')
    message = lst.msg_list
    print('Waiting for messages "%s"' % message)
    time.sleep(10)
    conn.disconnect()
    return ''

我不确定为什么我的消息没有显示在输出中,而是总是显示“ Response:null”。

1 个答案:

答案 0 :(得分:1)

编辑:如@Petesh所指出,问题来自stompy(外部库),尚未移植到Python3。

如果您检查源代码,则可以找到以下内容:

except socket.timeout, exc:

这是python3 +的无效语法

如果您在python3.6 / 3.7环境中运行Lambda,则语法无效。

如果选择python 2.7,问题可能会消失,但是您还必须调整代码,库等。