类型'Observable <>不存在属性'filter'

时间:2018-11-21 08:49:51

标签: angular rxjs angular6 rxjs6 angular-ngselect

enter code here


    getHospital(term: string = null): Observable<Hospitals[]> {
    let items = this.getHospitals1();
    if (term) {
      items = items.filter(x => x.name.toLocaleLowerCase().indexOf(term.toLocaleLowerCase()) > -1);

    }
    return items.pipe(delay(500));;
  }



getHospitals1() : Observable<Hospitals[]>{

     return this.http.get<Hospitals[]>('https://my-json-server.typicode.com/monsterbrain/FakeJsonServer/hospitals')

   }

添加过滤器时出现错误 它是使用ng-select的dropdownlist的代码。它基于基于文本的搜索 我在这里使用angular7和rxjs 6

1 个答案:

答案 0 :(得分:2)

要使用filter运算符,您需要在pipe()内使用它:

import { filter } from 'rxjs/operators';

...

if (term) {
  items = items.pipe(
    filter(x => x.name.toLocaleLowerCase().indexOf(term.toLocaleLowerCase()) > -1),
  );
}