Question

运行此文件时，输出到我的文件的文本看起来像这样[Lpeople.Person; @ 33909752，我不确定如何将其更改为人的姓名和年龄

Johnta Kamerling，34岁
尼古拉·特斯拉，33岁

按升序排序

while ((line = reader.readLine()) != null) {
                //Creates an integer arraylist peopleAge
                Person[] peopleAge = new Person[size];
                Person temp = null;

                for(int i = 0; i < size; i++) {
                    peopleAge[i] = entry[i];
                }
                //k number of passes 
                for (int k = 1; k < peopleAge.length; k++) {
                    for(int j = 0; j < peopleAge.length - 1; j++) {

                        // Compare left to right, not right to left.
                        if(peopleAge[j].getAge() > peopleAge[j + 1].getAge()) {

                            //swap peopleAge[j] with peopleAge[j+1]
                            temp = peopleAge[j];
                            peopleAge[j] = peopleAge[j + 1];
                            peopleAge[j + 1] = temp;
                        }
                    }
                }
                System.out.println(peopleAge);
                writer.write(peopleAge + System.getProperty("line.separator"));
            }
            System.out.println("check tempfile");
            reader.close();
            writer.close();
            return null;
    }

Answer 1

Integer.compare()就足够了：

@Override
public int compareTo(Person person) {
    return Integer.compare(this.age, person.getAge());
}

不要忘记为您的课程实现Comparable：

implements Comparable<Person>

如果您在类中实现了此功能，则可以通过以下方式对Person个对象的任何数组进行排序：

Arrays.sort(array);

Answer 2

我看不到您到底是什么问题，但是有一些注意事项。

使用Integer.compare方法和if语句毫无意义。

Integer.compareTo函数返回

如果obj1大于obj2，则值> 0
如果obj1小于obj2，则值<0
如果obj1等于obj2，则值== 0

因此，如果结果首先是== 0，则

{{1}}

将始终== 0

如何使用气泡排序对人进行排序？

2 个答案: