Question

最近，我建立了一个小型转换器，以某种结构将txt数据转换为xml，我选择了一个文件夹，程序遍历该文件夹中的所有文件，并以XML格式一起写入一个xml文档。

在文件夹中，我的数据名称如下：

Data.0001.txt

Data.0002.txt

Data.0003.txt

Data.0004.txt

Data.txt

以此类推

我只希望其中不包含零的文件，因为具有零的文件只是其他文件的备份副本，而且我有6000多个文件，我无法手动过滤它们

到目前为止，这是我的代码

 static void Main(string[] args)
    {
        FolderBrowserDialog SelectFolder = new FolderBrowserDialog();
        String path = @"C:\newpages";

        XmlDocument doc = new XmlDocument();
        XmlElement root = doc.CreateElement("Pages");

        if (SelectFolder.ShowDialog() == DialogResult.OK)
        {
            var txt = string.Empty;
            string[] Files = Directory.GetFiles((SelectFolder.SelectedPath));
            int i = 1;
            foreach (string path1 in Files)
            {              
                String filename = Path.GetFileNameWithoutExtension((path1));
                using (StreamReader sr = new StreamReader(path1))
                {
                    txt = sr.ReadToEnd();
                    XmlElement id = doc.CreateElement("Page.id");
                    id.SetAttribute("Page.Nr", i.ToString());
                    id.SetAttribute("Pagetitle",  filename);
                    XmlElement name = doc.CreateElement("PageContent");
                    XmlCDataSection cdata = doc.CreateCDataSection(txt);
                    name.AppendChild(cdata);
                    id.AppendChild(name);  // page id appenndchild         
                    root.AppendChild(id);  // roots appenedchild
                    doc.AppendChild(root); //Main root

                }
             i++;
            }
        }
        Console.WriteLine("finished");
        Console.ReadKey();

        doc.Save(Path.ChangeExtension(path, ".xml"));

    }
}

任何帮助都是非常好的人

Answer 1

GetFiles返回指定目录中的文件名。其返回类型为string[]，因此您可以轻松地应用Where来过滤file的名称，如下所示：-

 var files = Directory.GetFiles("PathToYourDirec").Where(name => !name.Contains("0"));

Answer 2

在字符串文件名上，您可以确保它不包含“ 0”

if(!filename.Contains("0"))
    {

    }

Answer 3

在Files变量上，您可以使用正则表达式过滤掉仅包含字母的文件名

var reg = new Regex(@"^([^0-9]*)$");
var files = Directory.GetFiles("path-to-folder")
                     .Where(path => reg.IsMatch(path))
                     .ToList();

Answer 4

解决此问题时，可以大大简化整个代码。您不需要StreamReader即可读取整个文件，还可以及早获取文件名并进行过滤，而不用进入foreach和过滤：

static void Main(string[] args)
{
    FolderBrowserDialog SelectFolder = new FolderBrowserDialog();
    String path = @"C:\newpages";

    XmlDocument doc = new XmlDocument();
    XmlElement root = doc.CreateElement("Pages");

    if (SelectFolder.ShowDialog() == DialogResult.OK)
    {
        // Don't declare txt here, you're overwriting and only using it in a nested loop, declare it as you use it there
        // var txt = string.Empty;

        //string[] Files = Directory.GetFiles((SelectFolder.SelectedPath));
        // Change to getting FileInfos
        var Files = new DirectoryInfo(SelectFolder.SelectedPath).GetFiles()
            // Only keep those who don't contain a zero in file name
            .Where(f=>!f.Name.Contains("0"));
        int i = 1;
        foreach (var file in Files)
        {
            //String filename = Path.GetFileNameWithoutExtension((path1));

            // Don't need a StreamReader not a using block, just read the whole file at once with File.ReadAllText
            //using (StreamReader sr = new StreamReader(path1))
            //{
                //txt = sr.ReadToEnd();

                var txt = File.ReadAllText(file.FullName);
                XmlElement id = doc.CreateElement("Page.id");
                id.SetAttribute("Page.Nr", i.ToString());
                id.SetAttribute("Pagetitle", file.FullName);
                XmlElement name = doc.CreateElement("PageContent");
                XmlCDataSection cdata = doc.CreateCDataSection(txt);
                name.AppendChild(cdata);
                id.AppendChild(name);  // page id appenndchild         
                root.AppendChild(id);  // roots appenedchild
                doc.AppendChild(root); //Main root
            //}
            i++;
        }
    }
    Console.WriteLine("finished");
    Console.ReadKey();

    doc.Save(Path.ChangeExtension(path, ".xml"));

}

我还建议您不要使用您正在使用的XML api，而要使用更新和更简单的linq to XML，因为这也将简化元素的创建，请参见下面的整个代码的非常简化版本： d用LINQ和XElements编写过

static void Main(string[] args)
{
    FolderBrowserDialog SelectFolder = new FolderBrowserDialog();
    String path = @"C:\newpages";

    var root = new XElement("Pages");

    if (SelectFolder.ShowDialog() == DialogResult.OK)
    {
        var FilesXML = new DirectoryInfo(SelectFolder.SelectedPath).GetFiles()
            .Where(f => !f.Name.Contains("0"))
            // Note that the index is 0 based, if you want to start with 1 just replace index by index+1 in Page.Nr
            .Select((file, index) => 
                new XElement("Page.id",
                    new XAttribute("Page.Nr",index),
                    new XAttribute("Pagetitle",file.FullName),
                    new XElement("PageContent",
                        new XCData(File.ReadAllText(file.FullName))
                    )));
        // Here we already have all your XML ready, just need to add it to the root

        root.Add(FilesXML);
    }
    Console.WriteLine("finished");
    Console.ReadKey();

    root.Save(Path.ChangeExtension(path, ".xml"));

}

Answer 5

您可以尝试这样做，但是我建议您是否更改创建备份文件名称的逻辑。它不应以“ 0”作为字符，而应在文件名中提及诸如“ backup”之类的固定文本。

static void Main(string[] args)
    {
        FolderBrowserDialog SelectFolder = new FolderBrowserDialog();
        String path = @"C:\newpages";

        XmlDocument doc = new XmlDocument();
        XmlElement root = doc.CreateElement("Pages");

        if (SelectFolder.ShowDialog() == DialogResult.OK)
        {
            var txt = string.Empty;
            string[] Files = Directory.GetFiles((SelectFolder.SelectedPath));

            int i = 1;
            foreach (string path1 in Files)
            {
                String filename = Path.GetFileNameWithoutExtension((path1));

                if (!filename.Contains(".0"))
                {
                    using (StreamReader sr = new StreamReader(path1))
                    {
                        txt = sr.ReadToEnd();
                        XmlElement id = doc.CreateElement("Page.id");
                        id.SetAttribute("Page.Nr", i.ToString());
                        id.SetAttribute("Pagetitle",  filename);
                        XmlElement name = doc.CreateElement("PageContent");
                        XmlCDataSection cdata = doc.CreateCDataSection(txt);
                        name.AppendChild(cdata);
                        id.AppendChild(name);  // page id appenndchild         
                        root.AppendChild(id);  // roots appenedchild
                        doc.AppendChild(root); //Main root

                    }

                }


             i++;
            }
        }
        Console.WriteLine("finished");
        Console.ReadKey();

        doc.Save(Path.ChangeExtension(path, ".xml"));

    }

如何从一个名称不包含0的目录中获取所有文件？

5 个答案: