Question

我正在尝试从2018-11-28 08:52:48.881 UTC [fsblkstorage] newBlockfileMgr -> INFO 004 Getting block information from block storage 2018-11-28 08:52:48.920 UTC [orderer/commmon/multichannel] checkResourcesOrPanic -> CRIT 005 [channel byfn-sys-channel] config requires unsupported channel capabilities: Channel capability V1_3 is required but not supported: Channel capability V1_3 is required but not supported panic: [channel byfn-sys-channel] config requires unsupported channel capabilities: Channel capability V1_3 is required but not supported: Channel capability V1_3 is required but not supported元素中获取选定的选项值。

select

尝试访问<form method="post" action="training/save" enctype="multipart/form-data" id="trainingForm"> <select name="trainees[]" id="trainees" class="form-control" required multiple="multiple"> <option value="1">1</option> </select> <button type="submit">Submit</button> </form>值时得到undefined：

select

我可以通过其他方式（通过ID）获取值：

$('#trainingForm').submit( function (){
  console.log($(this).find('select[name="trainees"]').val());
});

注意：正在使用$('#trainees').val();。

但是我想以以前的方式获取值。

Answer 1

[]也是元素 name 属性的一部分。您必须将其包括在选择器中：

$(document).ready(function() {
    $('#trainees').select2();
});

$('#trainingForm').submit( function (){
  console.log($(this).find('select[name="trainees[]"]').val());
  return false;
});

<link href="https://cdnjs.cloudflare.com/ajax/libs/select2/4.0.6-rc.0/css/select2.min.css" rel="stylesheet" />
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/select2/4.0.6-rc.0/js/select2.min.js"></script>

<form method="post" action="training/save" enctype="multipart/form-data" id="trainingForm">
    <select name="trainees[]" id="trainees" class="form-control" required multiple="multiple">
        <option value="1">1</option> 
        <option value="2">2</option>
    </select>
<button type="submit">Submit</button>
</form>

Answer 2

只需更改您的

$('#trainingForm').submit( function ()
{
  console.log($(this).find('select[name="trainees"]').val());
});

到

$('#trainingForm').submit( function ()
{
  console.log($(this).find('select[name="trainees[]"]').val());
});

您需要提供与html中相同的名称。

选择元素$（this）.find（）不起作用

2 个答案: