Question

问题是：我有方法

def comparison_reporter(list_of_scenarios_results1, list_of_scenarios_results2)
  actual_failed_tests = list_of_scenarios_results2.select {|k,v| v == 'Failed'}
  actual_passed_tests = list_of_scenarios_results2.select {|k,v| v == 'Passed'}
  failed_tests = Array.new(actual_failed_tests.length) { Hash.new }
  failed_tests.each do |hash|
      actual_failed_tests.keys.map {|name| hash["test_name"] = name}
      actual_failed_tests.values.map {|new_status| hash["actual_status"] = new_status}
      list_of_scenarios_results1.values_at(*actual_failed_tests.keys).map {|old_status| hash["previous_status"] = old_status}
  end
  final_result = {
    "passed_tests_count" => list_of_scenarios_results2.select {|k,v| v == 'Passed'}.length,
    "failed_tests_count" => list_of_scenarios_results2.select {|k,v| v == 'Failed'}.length,
    "failed_tests" => failed_tests
  }
  return final_result
end

此方法以2个哈希作为参数，并返回它们比较的结果和其他一些东西。当前，它总是返回带有两个（或更多）相同散列（相同键值对）的failed_tests。我认为，该问题在failed_tests.each do |hash|块中的某个地方，但是我找不到此错误的原因，请提出建议。方法结果示例（.json格式）

{
  "passed_tests_count": 3,
  "failed_tests_count": 2,
  "failed_tests": [
    {
      "test_name": "As a user I want to use Recent searches tab",
      "actual_status": "Failed",
      "previous_status": "Failed"
    },
    {
      "test_name": "As a user I want to use Recent searches tab",
      "actual_status": "Failed",
      "previous_status": "Failed"
    }
  ]
}

UPD： hash1（第一个参数）-

{""=>"Passed",
"As a new user I want to use no fee rentals tab"=>"Passed",
"As a new user I want to use Luxury rentals tab"=>"Passed", 
"As a user I want to use Recent searches tab"=>"Failed",
"As a user I want to use new listings for you tab"=>"Passed"}

hash2（第二个参数）-

{""=>"Passed",
"As a new user I want to use no fee rentals tab"=>"Failed",
"As a new user I want to use Luxury rentals tab"=>"Passed",
"As a user I want to use Recent searches tab"=>"Failed",
"As a user I want to use new listings for you tab"=>"Passed"}

所需输出示例：

{ 
"passed":"count",
"failed":"count",
"failed_tests": [
   {"test_name":"As a user I want to use Recent searches tab",
    "actual_status":"failed",
    "previous_status":"failed"},
   {"test_name":"As a new user I want to use no fee rentals tab",
    "actual_status":"failed",
    "previous_status":"passed"}]
}

Answer 1

解决方案：

services.AddSwaggerGen(c =>
        {
            c.SwaggerDoc("v1", new Info
            {
                Title = "ASP.NET Core 2.1+ ConsumerApp API",
                Version = "v1"
            });
            // Set the comments path for the Swagger JSON and UI.
            var xmlFile = $"{Assembly.GetExecutingAssembly().GetName().Name}.xml";
            var xmlPath = Path.Combine(AppContext.BaseDirectory, xmlFile);
            c.IncludeXmlComments(xmlPath);
            c.CustomSchemaIds(i => i.FullName);
        });

简化了def comparison_reporter(before, after) failed_tests = after.select { |k,v| v == "Failed" }.map do |k,v| { test_name: k, actual_status: v, previous_status: before[k] } end { passed: after.size - failed_tests.size, failed: failed_tests.size, failed_tests: failed_tests } end。由于我们可以计算失败测试的数量，因此我们可以将其用于最终计数，而不必再次遍历哈希。

Answer 2

问题出在第8行：您将hash["previous_status"]中的最后一个值覆盖到list_of_scenarios_results1.values_at(*actual_failed_tests.keys)上。

通常，您使用map来为某个对象分配一个可迭代对象，而不修改其他对象。例如
x = ['1','2','3'].map(&:to_i)
而不是
x = []; ['1','2','3'].map {|v| x << v.to_i}

我建议您重新考虑您的方法。您是否在两个哈希中始终具有相同的密钥？如果是这样，您可以简化此过程。我也建议您研究byebug。这是一个交互式调试器，可让您逐步执行功能，并查看未按预期进行的事情。

Ruby-在哈希数组中设置键值对

2 个答案: