Question

我发现我的应用程序中存在一个错误，该错误中的sql语句未显示正确的结果。我不需要从OR到特定iban的表中的每笔交易：

$limit_offset = ceil(date('W') / 3) - 1;
$query = "SELECT id FROM your_table ORDER BY id LIMIT $limit_offset, 3";

目前，它仅显示来自所选iban的交易，事实是也有传入的交易：

 SELECT *
 FROM BANKING.TRANSTAB                                                            
 WHERE ABSENDER = 'DE71419330598239161300'                                    
         OR EMPF = 'DE71419330598239161300'                                           
         AND                                                                          
         TIME BETWEEN TO_DATE('2018-10','YYYY-MM')                                    
         AND TO_DATE('2018-12','YYYY-MM');                                            
------+---------+---------+---------+---------+---------+---------+---------+---------+---
  ROW_ID  ABSENDER                EMPF                                     SUMME  ZWECK   
------+---------+---------+---------+---------+---------+---------+---------+---------+---
      98  DE71419330598239161300  DE38820942858809256538                   10.45  test    
      99  DE71419330598239161300  DE38820942858809256538                   23.42  test    
     102  DE71419330598239161300  DE38820942858809256538                   12.00  123     
     103  DE71419330598239161300  DE38820942858809256538                   12.00  12      
     104  DE71419330598239161300  DE38820942858809256538                   12.00  123     
     105  DE71419330598239161300  DE38820942858809256538                  123.00  123

Answer 1

如果使用OR，则需要在方括号内使用所有OR条件。

SELECT * FROM BANKING.TRANSTAB                                                            
     WHERE (ABSENDER = 'DE71419330598239161300'                                    
     OR EMPF = 'DE71419330598239161300')
     AND                                                                          
     TIME BETWEEN TO_DATE('2018-10','YYYY-MM')                                    
     AND TO_DATE('2018-12','YYYY-MM');

带OR的SQL语句未同时显示两种情况

1 个答案: