如何访问数组内部的对象数组?

时间:2018-12-03 04:51:01

标签: javascript reactjs react-native

[
    {
        name:"Technology",
        logoImage:require("../../assets/g837.png"),
        subCategory:[
            "IT",
            "Networks",
            "Appliances",
            "Industrial Machines",
            "Medical technology",
            "robotics",
            "AI",
            "Electronics",
            "Explosives",
            "Machinery", 
            "Cryptocurrency",
            "Electric Vehicles",
            "Biotechnology"

        ]
    },
    {
        name:"Business",
        logoImage:require("../../assets/business.png"),
        subCategory:[
            "Industries",
            "Economics",
            "Journalism",
            "Labor",
            "Law",
            "Real estate",
            "Entrepreneurship",
            "Investment",
            "Banking",
            "Leadership",
            "Advertising",
            "Business Strategy", 
            "Marketing",
            "E-commerce"
        ]
    },
    {
        name:"Entertainment",
        logoImage:require("../../assets/entertainment.png"),
        subCategory:[
            "Comedy",
            "Dance",
            "Dramas",
            "Films",
            "Gaming",
            "Toys",
            "Gambling",
            "Comics",
            "Social sites"

        ]
    }
]

3 个答案:

答案 0 :(得分:0)

假设您用于存储JSON的变量称为{ "MOCType":"Temporary Repair","MOCStatusUpdatedDateTime":"2018-10-31T10:00:00Z","TagNumber":"4850-A-101-A01A,4850-A-101-A03C,4850-A-101-A08,4850-A-101-A10A,4850-A-101-A10B,4850-A-101-A10C,4850-A-101-A11,4850-A-101-A12,6320-T-003C","Id":"CLX000A" } ,您会做的

{
"4850-A-101-A01A" :{
"Temporary Repair (eMOC)": "OK"
},

"4850-A-101-A03C" :{
"Temporary Repair (eMOC)": "OK"
},

"4850-A-101-A08" :{
"Temporary Repair (eMOC)": "OK"
},

"4850-A-101-A10B" :{
"Temporary Repair (eMOC)": "OK"
}
} 

在for循环中,您还可以循环访问数组的所有子类别。

答案 1 :(得分:0)

const myArray = [
    {
        "subCategory":[
            "IT",
            "Networks"
        ]
    },
    {
        "subCategory":[
            "IT",
            "Networks"
        ]
    }
]

myArray.forEach((eachObject) => {
  console.log(eachObject.subCategory)
})

假设您已将该数组存储在变量 myArray

然后,您可以在forLoop的帮助下轻松地迭代subCategory的值。

myArray.forEach((eachObject) => {
    console.log(eachObject.subCategory)
})

答案 2 :(得分:0)

如果这只是一个简单的JS问题,请访问数组/对象中的某些数据。...

要访问数组中的元素:

array[index] // first element start from 0.

上面的“元素”可以视为字符串,数字,对象甚至是数组内部的数组。

要访问对象内部的元素,请执行以下操作:

let obj = {a:100,b:200,c:300}

object.key //obj.a means will get the value of 100

object["key"] //obj["b"] means will get the value of 200

let x = "c"

object[variable] // obj[x] is equal to obj["c"] means will get the value of 300.

因此,要从对象数组中的数组访问“ subCategory”,只需组合以上策略即可:

var nestedArray = [
    {
        name:"Technology",
        logoImage:require("../../assets/g837.png"),
        subCategory:[
            "IT",
            "Networks",
            "Appliances",
            "Industrial Machines",
            "Medical technology",
            "robotics",
            "AI",
            "Electronics",
            "Explosives",
            "Machinery", 
            "Cryptocurrency",
            "Electric Vehicles",
            "Biotechnology"

        ]
    },
    {
        name:"Business",
        logoImage:require("../../assets/business.png"),
        subCategory:[
            "Industries",
            "Economics",
            "Journalism",
            "Labor",
            "Law",
            "Real estate",
            "Entrepreneurship",
            "Investment",
            "Banking",
            "Leadership",
            "Advertising",
            "Business Strategy", 
            "Marketing",
            "E-commerce"
        ]
    },
    {
        name:"Entertainment",
        logoImage:require("../../assets/entertainment.png"),
        subCategory:[
            "Comedy",
            "Dance",
            "Dramas",
            "Films",
            "Gaming",
            "Toys",
            "Gambling",
            "Comics",
            "Social sites"
        ]
    }
]


var subCategoryArray = nestedArray[0]["subCategory"] // return  ["IT", "Networks",...]

如果阵列中有多个对象,则需要使用for循环:

var subCategoryArray = []
for(var i = 0; i < nestedArray.length; i++){
   subCategoryArray= subCategoryArray.concat(nestedArray[i]["subCategory"])
}

console.log(subCategoryArray) //return ["IT", "Networks",...,"Comics","Social sites"]
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