玩Python并测试我的技能，我想构建一个Python脚本，该脚本以在D＆D 5E中创建角色的规则为中心。 到目前为止的脚本：
for x in range (1):
strength.append(random.randint(3,18))
str_score = strength
Ability_Score_Modifiers = {'1' : '-5',
'2' : '-4',
'3' : '-4',
'4' : '-3',
'5' : '-3',
'6' : '-2',
'7' : '-2',
'8' : '-1',
'9' : '-1',
'10' : '0',
'11' : '0',
'12' : '+1',
'13' : '+1',
'14' : '+2',
'15' : '+2',
'16' : '+3',
'17' : '+3',
'18' : '+4',
'19' : '+4',
'20' : '+5',
'21' : '+5',
'22' : '+6',
'23' : '+6',
'24' : '+7',
'25' : '+7',
'26' : '+8',
'27' : '+8',
'28' : '+9',
'29' : '+9',
'30' : '+10'}
for keys in Ability_Score_Modifiers.keys() and str_score:
if Ability_Score_Modifiers.keys([str_score]) == Ability_Score_Modifiers.keys():
print ('True', value)
else:
pass
我遇到的问题是让脚本查看技能生成的值，并对照我的字典对其进行检查，然后返回与该技能返回的数字相匹配的各个键的值。
这是一个摘要，来源在这里5E Character creator - python edition
我已经在这里待了大约一天半了，而我却空白了。当然，我在工作时使用pythonfiddle进行练习，所以不会出现逻辑错误。
谢谢
答案 0 :(得分：1)
好的，所以我得到的是： 您正在生成随机强度得分。您想将其与指定静态分数和修饰符之间关系的字典进行比较。 应该足够简单。试试这个：
<form enctype="multipart/form-data" action="add.php" method="POST">
Stocknr: <input type="text" name="stocknr">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Alphanumerical, No Spacing, Max 25 Characters**</p>
<br><br>
Year: <input type="text" name="year">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Numbers Only, Max 5 Character**</p>
<br><br>
Brand: <input type="text" name="brand">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Max 20 Characters**</p>
<br><br>
Model: <input type="text" name="model">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Max 20 Characters**</p>
<br><br>
<?php
$servername = "servername";
$dbusername = "username";
$dbpassword = "password";
$dbname = "dbname";
$con=mysqli_init();
if (!$con)
{
die("mysqli_init failed");
}
if (!mysqli_real_connect($con,$servername,$dbusername,$dbpassword,$dbname))
{
die("Connect Error: " . mysqli_connect_error());
}
echo "<font face='krona-one' size='3'>Vehicle Type:";
echo "<select name='class' 'class' class='class'><option value='all'><font
face='krona-one' size='3'>Select</option>";
mysqli_select_db($con,"$dbname");
$sql = "SELECT type FROM class";
$result = mysqli_query($con,$sql);
while ($row = mysqli_fetch_array($result)) {
echo "<option value='" . $row['type'] ."'>" . $row['type'] ."</option>";
}
echo "</select>";
?>
<br><br>
Mileage: <input type="text" name = "mileage">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Numbers, No Spacing, Max 25 Characters**</p>
<br><br>
Colour: <input type="text" name = "colour">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Max 20 Characters, No Spacing**</p>
<br><br>
Transmission: <input type="text" name = "trans">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Max 20 Characters, No Spacing**</p>
<br><br>
Fuel: <input type="text" name = "fuel">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Max 20 Characters**</p>
<br><br>
Description: <br><textarea name="description" rows="4" cols="40">
</textarea><br><br>
Price: <input type="text" name = "price">
<p style="font-family:krona-one,sans-serif;colour:#ffffff;"
size="18px">**Numbers Only, No Spacing, Leave out "R"**</p>
<br><br>
Photo: <input type="file" name="photo"><br>
Photo2: <input type="file" name="photo2"><br>
Photo3: <input type="file" name="photo3"><br>
Photo4: <input type="file" name="photo4"><br>
Photo5: <input type="file" name="photo5"><br>
Photo6: <input type="file" name="photo6"><br>
Photo7: <input type="file" name="photo7"><br>
Photo8: <input type="file" name="photo8"><br>
Photo9: <input type="file" name="photo9"><br>
Photo10: <input type="file" name="photo10"><br>
<br>
<input type="submit" value="Add" >
</form>
之所以起作用，是因为我们要说的是，起初，我们要遍历修饰符字典中的每个键（左侧）。如果当前键的 右 侧等于强度强度得分相等的键的右侧，则打印True。从功能上讲，我不确定为什么要测试布尔相等性，但是无论哪种方式都应该这样做。让我知道它是否有效！
以下是一些代码：
for key in Ability_Score_Modifiers:
if Ability_Score_Modifiers[key] == Ability_Score_Modifiers[int(str_score)]:
print('True', value)
输出：
import random
str_score = str(random.randint(3,18))
Ability_Score_Modifiers = {'1' : '-5', '2' : '-4', '3' : '-4', '4' : '-3', '5' : '-3', '6' : '-2', '7' : '-2', '8' : '-1', '9' : '-1', '10' : '0', '11' : '0', '12' : '+1', '13' : '+1', '14' : '+2', '15' : '+2', '16' : '+3', '17' : '+3', '18' : '+4', '19' : '+4', '20' : '+5', '21' : '+5', '22' : '+6', '23' : '+6', '24' : '+7', '25' : '+7', '26' : '+8', '27' : '+8', '28' : '+9', '29' : '+9', '30' : '+10'}
for key in Ability_Score_Modifiers:
if Ability_Score_Modifiers[key] == Ability_Score_Modifiers[str_score]:
print("True")
print("Stat score of {} grants a modifier of {}".format(str_score, Ability_Score_Modifiers[str_score]))
也许以后会派上用场的！
True
Stat score of 15 grants a modifier of +2
True
Stat score of 15 grants a modifier of +2
输出：
import random
#Generate our Str, Dex, Con, Int, Wis, Cha
Ability_Scores = {}
for n in ['Str', 'Dex', 'Con', 'Int', 'Wis', 'Cha']:
Ability_Scores[n] = str(random.randint(3,18))
Ability_Score_Modifiers = {'1' : '-5', '2' : '-4', '3' : '-4', '4' : '-3', '5' : '-3', '6' : '-2', '7' : '-2', '8' : '-1', '9' : '-1', '10' : '0', '11' : '0', '12' : '+1', '13' : '+1', '14' : '+2', '15' : '+2', '16' : '+3', '17' : '+3', '18' : '+4', '19' : '+4', '20' : '+5', '21' : '+5', '22' : '+6', '23' : '+6', '24' : '+7', '25' : '+7', '26' : '+8', '27' : '+8', '28' : '+9', '29' : '+9', '30' : '+10'}
for score in Ability_Scores:
print("{} score of {} grants a modifier of {}".format(score, Ability_Scores[score], Ability_Score_Modifiers[Ability_Scores[score]]))
发现它比我们想象的还要简单！
Str score of 7 grants a modifier of -2
Dex score of 12 grants a modifier of +1
Con score of 17 grants a modifier of +3
Int score of 8 grants a modifier of -1
Wis score of 12 grants a modifier of +1
Cha score of 5 grants a modifier of -3
因此，在执行If语句时，您甚至不需要使用字典索引进行比较。您只需使用迭代器中的“键”并将其与能力得分进行比较即可。