同一帖子显示在每个标题和帖子中

时间:2018-12-06 22:05:11

标签: javascript php mysqli

大家好,我只是想知道为什么我的Viewpost.php 在同一用户的每个标题中显示相同的帖子? 我尝试查找为什么_GET显示相同的帖子 现在我迷路了,所以如果有人知道为什么它为同一位用户显示相同的帖子,那么每个帖子都很棒

我知道我每次做这样的事都要备份

现在我知道了:(

代码

<?php
     $page = $_GET['page'];
     $sql = "SELECT * FROM `news` LEFT JOIN `admin` ON admin.id = news.username WHERE admin.id = '$page' LIMIT 1";
     $result = mysqli_query($link, $sql);
     if( $result )    
     while($blog = mysqli_fetch_assoc($result) ) {
    ?>       
          <div class="card mb-4">
            <div class="card-body">           
            <div class="dropdown-divider"></div>
              <h2 class="card-title"><?php echo $blog["title"]; ?></h2>
              <?php  
              echo '</br>';
            if ($blog['sponored'] === "SPONSORED") {
echo '<span class="badge badge-pill badge-success  pull-right"><sponored>'. $blog['sponored'] .'</sponored></span>';  
      } else {
echo '<span class="badge badge-pill badge-info pull-right"><post>' . $blog['sponored'] . '</post></span>';
 } 
?>                               
<div class="dropdown-divider"></div> </br>

<?php echo $blog["content"]; ?>
              <p class="card-text">
              </p>                       
            </div>            
            <div class="card-footer text-muted">
            <div class="dropdown-divider"></div>
<span class="badge badge-pill badge pull-left"><light-css>author </light-css>
    <a href='/<?php echo $blog["id"]; ?>/<?php echo $blog["username"]; ?>.php'><user-css><?php echo $blog["username"]; ?></user-css></a>   
</span>
<span class="badge badge-pill badge pull-right"><light-css>Time</light-css><admin-css><?php echo date('h:i A' , strtotime($blog['Published']));?></admin-css></span>                          
 <span class="badge badge-pill badge pull-right"><light-css>on</light-css><admin-css><?php echo date('l jS F Y' , strtotime($blog['Published']));?></admin-css></span>                          
                       
 <div id='disqus_thread'></div>
        <script type='text/javascript'>
          /* * * CONFIGURATION VARIABLES: EDIT BEFORE PASTING INTO YOUR WEBPAGE * * */
          var disqus_shortname = '<?php echo $row["disqus"]; ?>'; // required: replace example with your forum shortname
              (function() {
              var dsq = document.createElement('script'); dsq.type = 'text/javascript'; dsq.async = true;
              dsq.src = '//' + disqus_shortname + '.disqus.com/embed.js';
              (document.getElementsByTagName('head')[0] || document.getElementsByTagName('body')[0]).appendChild(dsq);
          })();
        </script>
            </div>
            <div class="dropdown-divider"></div>           
            <a href="<?php echo $row['siteurl']; ?>">home</a>
            </br>
        </div>       
       <?php } ?>

0 个答案:

没有答案