Question

我有一个查询在核心工作时间（7：30-16：30）之间循环。该查询返回每个组直到日期的最新预订，但我似乎无法弄清楚确保最新返回的信息是截至循环时间

的条件。

即今天的07:30，无论记录记录的日期如何，F01-F03组的最新预订都是... 。

此刻我的查询如下：

DECLARE @ALLBOOKINGS TABLE (BOOKING_GRP NVARCHAR(3), BOOKING_DATE DATETIME)
DECLARE @MAX_BACKDATE DATE = dateadd(DAY,datediff(DAY,0,getdate())-5,0), 
@CURRENT_TIME TIME(0) = GETDATE(),
@START_TIME TIME(0) = '07:30:00';

BEGIN 
    INSERT INTO @ALLBOOKINGS
        SELECT BOOKING_GRP, BOOKING_DATE
    FROM TABLE1 
    WHERE BOOKING_DATE >= @MAX_BACKDATE  
END

WHILE (@START_TIME <= @CURRENT_TIME)
    BEGIN   
    SELECT * 
      FROM @ALLBOOKINGS AS T1
    WHERE BOOKING_DATE = (SELECT MAX(BOOKING_DATE) FROM @ALLBOOKINGS WHERE BOOKING_GRP = T1.BOOKING_GRP)
    --AND
    --cast(BOOKING_DATE as time(0)) > @START_TIME AND cast(BOOKING_DATE as time(0)) < @CURRENT_TIME <<<<<<<<<<<<<<<<< this does not work, only returns max till now

    SET @START_TIME = DATEADD(MINUTE,10,@START_TIME) END

表格：

+-------+-----------+-----------+-------------+-----------+-------------+
|   BOOKING_GRP     |        BOOKING_DATE     |        @START_TIME      |
+-------+-----------+-----------+-------------+-----------+-------------+
|      F01          | 2018-12-10 11:48:50.363 |      07:30:00           |
|      F02          | 2018-12-10 11:22:06.367 |      07:30:00           |
|      F03          | 2018-12-10 11:21:14.240 |      07:30:00           |
+-------+-----------+-----------+-------------+-----------+-------------+
FAKE DATA - CURRENT RESULT

+-------+-----------+-----------+-------------+-----------+-------------+
|   BOOKING_GRP     |        BOOKING_DATE     |       @START_TIME       |
+-------+-----------+-----------+-------------+-----------+-------------+
|      F01          | 2018-12-07 10:34:50.363 |      07:30:00           |
|      F02          | 2018-12-10 12:32:06.367 |      07:30:00           |       
|      F03          | 2018-12-06 11:37:14.240 |      07:30:00           |     
+-------+-----------+-----------+-------------+-----------+-------------+

预期结果-在最近5天之内，截至今天07:30，每组最近的预订量

Answer 1

我不确定我是否完全理解这个问题，但是您可以尝试以下查询：

SELECT Booking_Group, MAX (Booking_Date) AS MaxDate
FROM SomeTable AS ST
WHERE Booking_Date BETWEEN DATEADD (MINUTE, 30, DATEADD (HH, 7, CAST (CAST (GETDATE() AS DATE) AS DATETIME)) ) AND GETDATE() 
GROUP BY Booking_Group

Answer 2

没有循环的理由。

declare @start datetime = '20180101'
   ,@end datetime = getdate()

select BOOKING_GRP,max(BOOKING_DATE) as LATEST_BOOKING_DATE
from Table1
where BOOKING_DATE between @start and @end
group by BOOKING_GRP

Answer 3

已通过在while条件中添加DATE来解决

DECLARE @STARTTIME dateTIME = dateadd(day, datediff(day, 0, getdate()), 0) + '07:30',  
@CURRENTTIME DATETIME= GETDATE()

WHILE (@START_TIME <= @CURRENT_TIME)
    BEGIN   
    SELECT * 
      FROM @ALLBOOKINGS AS T1
    WHERE BOOKING_DATE = (SELECT MAX(BOOKING_DATE) FROM @ALLBOOKINGS WHERE BOOKING_GRP = T1.BOOKING_GRP
    AND DATE_BOOKED < @STARTTIME
    )

    SET @START_TIME = DATEADD(MINUTE,10,@START_TIME) END

特定时期内MAX（预订）的条件

3 个答案: