Question

要获得有关4台服务器的性能报告，我希望每周期每台服务器获得一个AVG，在这种情况下为1分钟。我可以获取每个服务器的COUNT和MAX，但不能获取AVG（stay）。每个服务器由CREATE_APP_LOC_ID列标识，其值分别为0、1、2或3。在查询中我该怎么做？

感谢您的帮助。

输出如下：

                     Overall                                           server_1                server_2                server_3                server_4 
                                   Max     Avg                                  Max    Avg              Max    Avg              Max    Avg              Max    Avg
End Time             TXN   TPS    Stay    Stay   Appr   Decl Other       TXN   Stay   Stay       TXN   Stay   Stay       TXN   Stay   Stay       TXN   Stay   Stay
---------------- ------- ----- ------- ------- ------ ------ ----- --------- ------ ------ --------- ------ ------ --------- ------ ------ --------- ------ ------
2018-12-10 16:40    2354    39     513      74   1345   1008     1       599    316     11       559     48      7       599    513     29       597    328     28

这是使用的查询：

ACCEPT start_time CHAR PROMPT 'Enter start time (yyyy-mm-dd hh:mm): '
ACCEPT stop_time CHAR PROMPT 'Enter end time (yyyy-mm-dd hh:mm)  : '

DEFINE time_diff = 1

SELECT TO_CHAR((MIN(end_time)+(&time_diff/24)), 'YYYY-MM-DD HH24:MI') c1, COUNT(*) c2,
       COUNT(*)/60 c3,
       MAX(stay) c4, ROUND(AVG(stay)) c5,
       SUM (CASE WHEN SUBSTR(TXN.RES_CODE,1,3) = 'APP' THEN 1 ELSE 0 END) c10,
       SUM (CASE WHEN SUBSTR(TXN.RES_CODE,1,3) = 'DEC' THEN 1 ELSE 0 END) c11,
       SUM (CASE WHEN SUBSTR(RES_CODE,1,3) <> 'APP' AND SUBSTR(RES_CODE,1,3) <> 'DEC' THEN 1 ELSE 0 END) c12,
/*server_1*/
       SUM (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 0 THEN 1 ELSE 0 END) c13,
       MAX (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 0 THEN stay ELSE 0 END) c20,
       AVG (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 0 THEN stay ELSE 0 END) c21, 
/*server_2*/
       SUM (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 1 THEN 1 ELSE 0 END) c14,
       MAX (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 1 THEN stay ELSE 0 END) c20,
       AVG (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 1 THEN stay ELSE 0 END) c21,
/*server_3*/
       SUM (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 2 THEN 1 ELSE 0 END) c15,
       MAX (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 2 THEN stay ELSE 0 END) c20,
       AVG (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 2 THEN stay ELSE 0 END) c21, 
/*server_4*/
       SUM (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 3 THEN 1 ELSE 0 END) c16,
       MAX (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 3 THEN stay ELSE 0 END) c20
       AVG (CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) = 3 THEN stay ELSE 0 END) c21  
FROM txn
WHERE txn_origin_id NOT IN (2,3)
  AND end_time >= '&start_time'
  AND end_time  < '&stop_time'
GROUP BY TO_CHAR(end_time, 'YYYY-MM-DD HH24:MI')
ORDER BY 1;

Answer 1

根据我的假设，由于ELSE 0部分，您得到了错误的AVG。尝试使用：

ROUND(AVG((CASE WHEN SUBSTR(CREATE_APP_LOC_ID, 1, 1) in (0,1,2,3) THEN stay ELSE 0 END))) c5,

代替

ROUND(AVG(stay)) c5,

使用CASE语句时的Oracle SQLPLUS AVG函数

1 个答案: