我有一列(非索引列),里面有日期时间。例如,前五个条目如下所示:
[Timestamp('2018-11-15 19:57:55'),
Timestamp('2018-11-15 19:59:46'),
Timestamp('2018-11-15 20:00:59'),
Timestamp('2018-11-15 20:01:41'),
Timestamp('2018-11-15 20:01:54')]
我要将条目从UTC转换为太平洋时区。假设该列名为times
,我目前正在执行以下操作:
times.dt.tz_localize('GMT').dt.tz_convert('America/Los_Angeles')
尽管此操作成功将列从UTC转换为PST,但输出中包含我不需要的无关组件。看起来如下:
[Timestamp('2018-11-15 11:57:55-0800', tz='America/Los_Angeles'),
Timestamp('2018-11-15 11:59:46-0800', tz='America/Los_Angeles'),
Timestamp('2018-11-15 12:00:59-0800', tz='America/Los_Angeles'),
Timestamp('2018-11-15 12:01:41-0800', tz='America/Los_Angeles'),
Timestamp('2018-11-15 12:01:54-0800', tz='America/Los_Angeles')]
如何从时间戳中删除或忽略-0800
?谢谢!
答案 0 :(得分:3)
只需添加.tz_localize(None)
的最后一步:
import pandas as pd
d = pd.Series(['2018-11-15 19:57:55', '2018-11-15 19:59:46'])
d = pd.to_datetime(d)
d
0 2018-11-15 19:57:55
1 2018-11-15 19:59:46
dtype: datetime64[ns]
d_pacific_tz_aware = d.dt.tz_localize("GMT").dt.tz_convert('America/Los_Angeles')
d_pacific_tz_aware
0 2018-11-15 11:57:55-08:00
1 2018-11-15 11:59:46-08:00
dtype: datetime64[ns, America/Los_Angeles]
d_pacific_tz_naive = d.dt.tz_localize("GMT").dt.tz_convert('America/Los_Angeles').dt.tz_localize(None)
d_pacific_tz_naive
0 2018-11-15 11:57:55
1 2018-11-15 11:59:46
dtype: datetime64[ns]