Question

我有一个表，其中有所有ID，第二个表中有ID，该进程中有错误。我需要查询选择错误发生之前的最后3个ID。例如：

first table:
id     |   info
___________________
100    |     1.0             
101    |     2.0                      
102    |     6.0             
103    |     9.0         
104    |     15.0         
105    |     8.0       
106    |     6.0
107    |     8.0       
108    |     6.0
109    |     8.0       
110    |     6.0



id of errors:

id        
____                                                              
104                 
110

因此，此查询将必须返回ID的值： 109,108,107,103,102和101

预先感谢

Answer 1

SELECT result.*
FROM errors e
CROSS APPLY (
    SELECT TOP 3 * 
    FROM [first table] ft 
    WHERE ft.id < e.id 
    ORDER BY ft.id DESC
) result

Answer 2

这可能对您有用：

设置：

Create Table #Errs
(
Id Int
);

Insert Into #Errs Values
(104), (110)

Create Table #tbl
(
Id Int,
Info Decimal(6,2)
);

Insert Into #tbl Values
(100,1.0),
(101,2.0),
(102,6.0),
(103,9.0),
(104,15.0),
(105,8.0),
(106,6.0),
(107,8.0),
(108,6.0),
(109,8.0),
(110,6.0)

查询

With cte As
(
   Select 
      Id,
      LAG(Id,1,Null) OVER(Order By Id) As iderror1,
      LAG(Id,2,Null) OVER(Order By Id) As iderror2,
      LAG(Id,3,Null) OVER(Order By Id) As iderror3 
   From #tbl t
) 
Select iderror1 As ErrorList From cte Where Id In (Select Id From #Errs)
Union ALL
Select iderror2 As ErrorList From cte Where Id In (Select Id From #Errs)
Union ALL
Select iderror3 As ErrorList From cte Where Id In (Select Id From #Errs)
Order By ErrorList

如果您的ID不是按顺序排列的，则可以使用（选择NULL），如下所示：

With cte As
(
   Select 
      Id,
      LAG(Id,1,Null) OVER(Order By (Select NULL)) As iderror1,
      LAG(Id,2,Null) OVER(Order By (Select NULL)) As iderror2,
      LAG(Id,3,Null) OVER(Order By (Select NULL)) As iderror3 
   From #tbl t
) 
Select iderror1 As ErrorList From cte Where Id In (Select Id From #Errs)
Union ALL
Select iderror2 As ErrorList From cte Where Id In (Select Id From #Errs)
Union ALL
Select iderror3 As ErrorList From cte Where Id In (Select Id From #Errs)
Order By ErrorList

结果

ErrorList
--------
101
102
103
107
108
109

Answer 3

您可以使用窗口函数来计算助手组SUM()和ROW_NUMBER()以获得最后3行：

WITH cte AS (
  SELECT t1.*, -sub.c+ SUM(sub.c) OVER(ORDER BY t1.id) AS grp
  FROM t1
  LEFT JOIN t2
    ON t1.id = t2.id
  CROSS APPLY (SELECT CASE WHEN t2.id IS NULL THEN 0 ELSE 1 END) sub(c)
), cte2 AS (
  SELECT *, ROW_NUMBER() OVER(PARTITION BY grp ORDER BY id DESC) rn
  FROM cte
)
SELECT id, info
FROM cte2
WHERE rn BETWEEN 2 AND 4
ORDER BY id;

db<>fiddle demo

比较2张桌子

3 个答案: