Question

底部的汉堡包的值不会乘以输入值菜单的次数。计数仅给我两个答案，它们不能正确输入实际的时间（菜单）。

def input1():
  menu = input("""
  hamburger--:  """)
  loop = input("Would you like to add another Food: (y/n)?")
  return menu, loop

def calc(menu, loop):
  hamburger = 1.25
  count = 1
  if menu == "h":
    print(loop)
  if loop == "y":
    menu, loop =input1()
    calc(menu, loop)

  if loop == "n":
    menu = (count)

    menu = int(count)
    print(menu * 1.25)
    count+=1

def main():
  menu, loop =input1()
  calc(menu, loop)

Answer 1

在递归调用中，您要添加每个值

<current value> + calc() + calc()....

赞：

def input1():
    menu = input("""
    hamburger--:  """)
    loop = input("Would you like to add another Food: (y/n)?")
    return menu, loop

def calc():
    # Get current value
    menu, loop = input1()
    cost = 0
    if 'h' == menu:
        cost = 1.25
    # Example other items
    elif 'f' == menu:   # Fries
        cost = .75
    # Make recursive calls, if needed
    if loop == "y":
        cost += calc()
    # Return the total (so far)
    return cost

def main():
    print(calc())

或者您可以将所有菜单项放在字典中：

full_menu = {'h': 1.25, 'f': .75, 's': 1.0}

def calc():
    menu, loop = input1()
    cost = 0
    if menu in full_menu:
        cost = full_menu[menu]
    if loop == "y":
        cost += calc()
    return cost

Answer 2

我认为（如果我正确理解了问题），问题在于您仅在最后一次迭代中执行“ count + = 1”。想象一下你这样做了两次

因为if循环==“ n”仅在您不想添加项目时发生。

以下是我认为coulf是更好的解决方案的建议：

PRICES = {
   'hamburger': 1.25
}

def get_input():
    menu_item = input('Item')
    loop = input("Would you like to add another Food: (y/n)?")
    return menu_item, loop

def calc():
  # Start a item count  
  item_count = {
      'hamburguer': 0
  }
  finished = False
  while not finished:
      menu_item, loop = get_input()
      # Check if item in menu
      if menu_item in PRICES.keys():
          item_count[menu_item] += 1
      else:
          print('Sorry, the item is not in the menue')
      # Check if no more items are expected  
      if loop == "n"
        finished = True

  return sum([ PRICES[item] * ammount (item, ammount) in item_count.values()])

def main():
  pritn(calc())

在函数中定义常量（如汉堡包价格）被认为是不好的做法。另外，覆盖参数（如菜单）可能会造成混淆。

我可能没有正确理解这个问题。但我希望这对您有帮助。不要犹豫，纠正我，对不起，英语不好

如何修复此功能？

2 个答案: