如何从联接表中获取多个值

时间:2018-12-13 21:29:00

标签: django django-orm

如何从订阅特定用户的所有课程中获得所有法律?

class Law(models.Model):
    name  = models.CharField('Nome', max_length=100)
    slug = models.SlugField('Atalho')
    description = models.TextField('Description', blank = True, null=True)

class Course(models.Model):
    name  = models.CharField('Nome', max_length=100)
    slug = models.SlugField('Atalho')
    description = models.TextField('Descrição', blank = True, null=True)
    laws = models.ManyToManyField(Law, related_name='law_course')


class Subscription(models.Model):    
    STATUS_CHOICES=(
        (
            (0, 'Pendente'),
            (1, 'Approved'),
            (2, 'Canceled'),
        )
    )
    user = models.ForeignKey(settings.AUTH_USER_MODEL,on_delete=models.CASCADE, verbose_name="Usuário", related_name="inscricao") #inscricao é criado no usuario
    course = models.ForeignKey(Course, on_delete=models.CASCADE, verbose_name="Course", related_name="subscription")
    status = models.IntegerField(
        'Status', choices=STATUS_CHOICES, default = 0, blank=True
        )

    class Meta:
        unique_together = (('user','course'))

因此,可以为用户订阅一门或多门课程。每门课程都有一个或多个法律。

我有一个页面,我需要列出如果已批准(status = 1的订阅,则特定用户订阅的每个课程的所有法律。 例: John用户已订阅了两门课程:课程A和课程B。

Course A laws: law1, law2, law3
Course B laws: law1, law20, law30

因此,当约翰登录时,我需要显示课程的法律和课程的名称:

law1 - Course A, Course B
law2 - Course A
law3 - Course A
law20 - Course B
law30 - Course B

请注意,我不能两次显示law 1,但是我显示了包含该定律的每门课程。

我尽力而为。提前Tks

1 个答案:

答案 0 :(得分:3)

您可以使用设置来存储法律(最终将是唯一的)。

laws_set = set()
subscriptions = Subscription.objects.filter(user=your_user, status=1)

对于每个订阅,请先学习该课程,然后获取与该课程相对应的所有法律。

for subscription in subscriptions:
    laws = subscription.course.laws.all() 

    for law in laws:
        laws_set.add(law)

现在,对于lawset中的每条法律,您都可以打印相应的课程。

for law in laws_set:
    print(law.name, end='')
    for course in law.law_course.all(): # Since law_course is the related name
        print(course.name, end='')
    print('\n')
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