Question

是否有任何管理模型方法，如get_list_display（）或某种方式我可以设置一些条件来设置不同的list_display值？

class FooAdmin (model.ModelAdmin):
    # ...
    def get_list_display ():
        if some_cond:
            return ('field', 'tuple',)
        return ('other', 'field', 'tuple',)

Answer 1

你有没有尝试过制作这个属性？

class FooAdmin(admin.ModelAdmin):
    @property
    def list_display(self):
        if some_cond:
            return ('field','tuple')
        return ('other','field','tuple')

我没有，但它可能有用。

我也很确定你可以拼写它：

class FooAdmin(admin.ModelAdmin):

    if CONDITION:
        list_display = ('field','tuple')
    else:
        list_display = ('other','field','tuple')

但是这个只会在解释FooAdmin类时运行检查：但是如果你将测试基于settings.SOME_VALUE，那么它可能会起作用。

另请注意，第一个示例中的self是FooAdmin类的实例，而不是Foo本身。

Answer 2

您想要覆盖admin.ModelAdmin类的changelist_view方法：

def changelist_view(self, request, extra_context=None):
  # just in case you are having problems with carry over from previous
  # iterations of the view, always SET the self.list_display instead of adding
  # to it

  if something:
    self.list_display = ['action_checkbox'] + ['dynamic_field_1']
  else:
    self.list_display = ['action_checkbox'] + ['dynamic_field_2']

  return super(MyModelAdminClass, self).changelist_view(request, extra_context)

'action_checkbox'是django用来知道在左侧显示操作下拉列表的复选框，因此请确保将其包含在设置self.list_display中。像往常一样，如果您只是为ModelAdmin类设置list_display，通常不需要包含它。

Answer 3

ModelAdmin类具有一个名为get_list_display的方法，该方法将请求作为参数，默认情况下返回该类的list_display属性。

因此，您可以执行以下操作：

class ShowEFilter(SimpleListFilter):
    """ A dummy filter which just adds a filter option to show the E column,
        but doesn't modify the queryset.
    """
    title = _("Show E column")
    parameter_name = "show_e"

    def lookups(self, request, model_admin):
        return [
            ("yes", "Yes"),
        ]

    def queryset(self, request, queryset):
        return queryset

class SomeModelAdmin(admin.ModelAdmin):

    list_display = (
      "a",
      "b",
      "c",
      "d",
      "e"
    )
    list_filter = (
        ShowEFilter,
    )


    def get_list_display(self, request):
        """ Removes the E column unless "Yes" has been selected in the 
            dummy filter.
        """
        list_display = list(self.list_display)
        if request.GET.get("show_e", "no") != "yes":
            list_display.remove("e")

        return list_display

Django Admin：有条件地设置list_display

3 个答案: