声明式管道共享库

时间:2018-12-18 13:48:41

标签: jenkins shared-libraries jenkins-pipeline

尝试在我的Jenkins服务器中实现共享库时遇到问题。

我遇到的错误与以下内容有关 No such DSL method 'agent' found among steps

我尝试删除代理并仅在节点上运行,但仍然存在问题。 我正在关注以下内容:https://jenkins.io/blog/2017/09/25/declarative-1/

有人可以指出我要去哪里了

vars / jenkinsJob.groovy

def call() {
    // Execute build pipeline job
    build_pipeline()
}

def build_pipeline() {
    agent {
       node {
          label params.SLAVE
      }
  }
        parameters {
            string(name: 'SETTINGS_CONFIG_FILE_NAME', defaultValue: 'maven.settings')
            string(name: 'SLAVE', defaultValue: 'new_slave')
        }

        environment {
            mvn = "docker run -it --rm --name my-maven-project -v "$(pwd)":/usr/src/mymaven -w /usr/src/mymaven maven:3.3-jdk-8"
        }

        stages {
            stage('Inject Settings.xml File') {
                steps {
                    configFileProvider([configFile(fileId: "${env.SETTINGS_CONFIG_FILE_NAME}", targetLocation: "${env.WORKSPACE}")]) {
                    }
                }
            }
            stage('Clean') {
                steps {
                    sh "${mvn} clean"
                }
            }
            stage('Lint') {
                steps {
                    sh "${mvn} lint"
                }
            }
            stage('Build package and execute tests') {
                steps {
                    sh "${mvn} build"
                }
            }
        }

        post {
            always {
                archive "**/target/surefire-reports/*"
                junit '**/target/surefire-reports/*.xml'
                step([$class: 'JacocoPublisher'])
            }
        }
    }

Jenkinsfile

@Library('pipeline-library-demo') _

jenkinsJob.call()

2 个答案:

答案 0 :(得分:0)

所有有效的声明性管道必须包含在管道块中 例如:

pipeline {
  /* insert Declarative Pipeline here */
  /* import libraries and call functions */
}

答案 1 :(得分:0)

文件jenkinsJob.groovy只需要一个名称即可使用单一方法:

def call(Map params[:]){
    // method body
}
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