删除重复的行，并通过max（datetime）保留最新的行

Question

下面的MySQL语句根据ADDRESS1和POSTCODE选择所有重复的行，其中最新行INSPECTION_DATE。本质上，它会选择我想要保留的所有内容。

SELECT COUNT(*), MAX(INSPECTION_DATE), ADDRESS1, POSTCODE, id
FROM epc 
GROUP BY ADDRESS1, POSTCODE 
HAVING COUNT(*) > 1;

我的问题是，如何删除所有较旧的重复项，并保留上述语句返回的重复项。

Answer 1

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DELETE  e
FROM epc e
INNER JOIN epc max_
ON e.address1 = max_.address1
   AND e.postcode = max_.postcode
   AND e.inspection_date < max_.inspection_date;

更新 http://sqlfiddle.com/#!9/8de866/1

DELETE  e
FROM epc e
INNER JOIN epc max_
ON e.address1 = max_.address1
   AND e.postcode = max_.postcode
   AND (e.inspection_date < max_.inspection_date
        OR (e.inspection_date = max_.inspection_date
           AND e.id < max_.id));