Question

在我的python代码中，我有两个可迭代的列表。

g = GeoIP2()
IP = '31.13.75.36'

def get_Ip(request):
    """Get IP.

    Notes:
        This function retrieves/gets IP's.

    Args:
        request:

    Returns:
        some object.

    Raises:
        ConnectionError.


    """
    x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
    try:
        ip = x_forwarded_for.split(',')[-1].strip()
    except Exception:
        ip = request.META.get('REMOTE_ADDR')
    return ip


def get_country(request):
    """Get country.

    """

    ip = Get_Ip(request)
    country = g.country(IP)
    return country

def get_browser(request):
    """Get Browser

    Notes:
        What should we know about this function.
        That is not already obvious.

    Args:
        request (type)

    Raises:

    Returns:

    """
    browser = request.META['HTTP_USER_AGENT']
    return browser

def save_vistor_data(request, slug):
    """Save visitor data to ...

    Notes:
        Where is the visitor data going?


    Args:
        request ():
        slug ():

    Returns:

    """
    ip = Get_Ip(request)
    country = Get_Country(request)
    browser = Get_Browser(request)

    _url = Url()
    url = Url.objects.get(slug=slug)

    victim = Victims(
        _url=url,
        ip_address=ip,
        country=country,
        browser=browser
    )

    victim.save()

    return HttpResponse('Done')

输出：

num = [1, 2, 3 ,4 ,5 ,6 ,]

alpa = ['a', 'b', 'c', 'd']

for (a, b) in itertools.izip_longest(num, alpa):

   print a, b

我的预期输出：

1 a
2 b
3 c
4 d
5 None
6 None

我该如何实现？

Answer 1

您可以使用itertools.cycle。这是一些Python 3代码。请注意，使用zip而不是izip_longest，因为cycle创建了一个无限迭代器，并且您希望在一个列表完成后停止。

import itertools

num = [1, 2, 3, 4, 5, 6] 

alpa = ['a', 'b', 'c', 'd'] 

for (a, b) in zip(num, itertools.cycle(alpa)):

   print(a, b)

如何遍历两个列表？

1 个答案: