我想在两列中比较两个不同日期范围的销售额。.我在下面使用查询,但给出了错误的销售额..请更正我的查询
select s1.Itm_cd,s1.Itm_Name,Sum(S1.amount),Sum(s2.amount)
from salestrans s1,salestrans s2
where s1.Itm_cd = S2.Itm_cd
and S1.Tran_dt between '20181101' and'20181130'
and S2.Tran_dt between '20171101' and '20171130'
group by s1.Itm_cd,s1.Itm_Name
Order by s1.Itm_cd
答案 0 :(得分:0)
我怀疑您要在此处进行条件聚合:
WITH cte AS (
SELECT
s1.Itm_cd,
s1.Itm_Name,
SUM(CASE WHEN s1.Tran_dt BETWEEN '20181101' AND '20181130'
THEN s1.amount ELSE 0 END) AS sum_2018,
SUM(CASE WHEN s1.Tran_dt BETWEEN '20171101' AND '20171130'
THEN s1.amount ELSE 0 END) AS sum_2017
FROM salestrans s1
GROUP BY
s1.Itm_cd,
s1.Itm_Name
)
SELECT
Itm_cd,
Itm_Name,
sum_2018,
sum_2017,
CASE WHEN COALESCE(sum_2017, 0) <> 0
THEN FORMAT(100.0 * (sum_2018 - sum_2017) / sum_2017, 'N', 'en-us')
ELSE 'NA' END AS growth_pct
FROM cte
ORDER BY
Itm_cd;
答案 1 :(得分:0)
请尝试以下
select s1.Itm_cd,s1.Itm_Name,Sum(S1.amount),Sum(s2.amount)
from salestrans s1,salestrans s2
where s1.Itm_cd = S2.Itm_cd
and Convert(Varchar(10),S1.Tran_dt,112) between '20181101' and'20181130'
and Convert(Varchar(10),S2.Tran_dt,112) between '20171101' and '20171130'
group by s1.Itm_cd,s1.Itm_Name
Order by s1.Itm_cd
这里的逻辑是,在进行比较时,右侧仅提供日期,不提供任何分隔符和时间。应该对左侧的列进行相同的比较。
if(Convert(Varchar(10), getdate(),112) = '20181224')
print 'Matched'
else
print 'Not Matched'
if(getdate() = '20181224')
print 'Matched'
else
print 'Not Matched'
在这里,输出首先是Matched
,而输出是Not Matched
,因为在第一种情况下,采用了双方相同的格式进行比较。