Question

我正在尝试将byteArray和一个String从当前活动传递到上一个片段。

public void uploadClick (View view) {
    //Send results back to previous screen
    switch (activity.from) {
        case "review" :
            if (activity.mCurrentPhotoPath != null && activity.bytes != null) {
                Intent reviewReturnIntent = new Intent();
                reviewReturnIntent.putExtra(ReviewsFragment.REVIEW_PHOTO_BITMAP, activity.bytes);
                reviewReturnIntent.putExtra(ReviewsFragment.REVIEW_PHOTO_PATH, activity.mCurrentPhotoPath);
                activity.setResult(Activity.RESULT_OK, reviewReturnIntent);
                activity.finish();
            }
            break;

        case "reply" :
            break;

        case "merchant" :
            break;

    }
}

onActivityResult片段：

 @Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    if (requestCode == REVIEW_REQUEST) {
        if (resultCode == getActivity().RESULT_OK) {
            if (data != null) {
                returnedBitmap = data.getByteArrayExtra(REVIEW_PHOTO_BITMAP);
                returnedPhotoPath = data.getStringExtra(REVIEW_PHOTO_PATH);

                Bitmap bmp = BitmapFactory.decodeByteArray(returnedBitmap, 0, returnedBitmap.length);
                binding.reviewIV.setImageBitmap(bmp);
                binding.returnedImageLayout.setVisibility(View.VISIBLE);
            }
        }
    }

}

startActivityForResult调用：

public void uploadClick (View view) {
    Intent uploadPhotoIntent = new Intent(fragment.getContext(), UploadPhotoActivity.class);
    uploadPhotoIntent.putExtra(UploadPhotoActivity.FROM, "review");
    fragment.startActivityForResult(uploadPhotoIntent, ReviewsFragment.REVIEW_REQUEST);
}

每次我尝试使用intent参数运行activity.setResult时。编译器将运行该代码，但不会完成该活动（因此，我无法返回上一个片段/活动）。我添加了断点，它运行“ setResult”和“ activity.finish（）”方法。但这似乎并没有破坏当前的活动。

尽管从“ setResult”方法中删除了intent参数后，一切正常，但是在上一个片段中，我从“数据”中返回了null。

示例：

activity.setResult(Activity.RESULT_OK);

曾经试图在互联网上寻找答案，但还是没有运气。非常感谢，并感谢您的阅读。：）

setResult（<resultcode>，<intent>）不起作用

0 个答案: