Question

我正在使用Haveibeenpwned API，但是遇到连续403错误的麻烦。我尝试使用Curl和file_get_contents，但结果相同...

 function Conn_mail($email){

        $headers = [            
            'User-Agent: Meu user agent'
        ];
        $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL,"https://haveibeenpwned.com/api/v2/breachedaccount/{$email}");
        curl_setopt($ch, CURLOPT_HEADER,true); //Retorna o Header na saída
        //if($headers){
            curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
        //}     
        curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
        curl_setopt($ch, CURLOPT_SSL_VERIFYPEER,0);

        $response = curl_exec($ch);
        return $response;
        /*var_dump($response);
        if (!$response){
            echo curl_error($ch);
        }*/ 

 }

 $json_hibp = Conn_mail('whatever@email.com');
echo $json_hibp;

和

 function Conn_mail($email){

    $context_options = array(
        'http' => array('user_agent' => 'custom user agent string')
        );

    $context = stream_context_create($context_options);         
    $con = file_get_contents("https://haveibeenpwned.com/api/v2/breachedaccount/{$email}",false,$context);
    echo "<pre>";
    print_r($http_response_header);
    echo "</pre>";
    $retorno = $http_response_header[0];
    if($retorno == 'HTTP/1.1 200 OK'){
        $ret = '200';
    }
    elseif($retorno == ' HTTP/1.1 404 Not Found'){
        $ret = '404';
    }
    else{
        $ret = $retorno;
    }
    return $ret;
 }

 $json_hibp = Conn_mail('whatever@email.com');
echo $json_hibp;

两个代码都包含“用户代理”标头，但是Haveibeenpwned API返回403错误（仅当缺少用户代理时才返回…）

怎么了？

谢谢

Answer 1

经过几次测试，CURLOPT_SSL_VERIFYHOST = 0（在Raymond解决方案中有注释）起作用。 file_get_contents在使用Haveibeenpwned API时不能很好地处理，甚至添加了强制性的“ User-Agent”标头...

具有Curl和file_get_contents的API

1 个答案: