Question

我正在使用此服务器，到目前为止，我已经修复了该服务器，因此无论何时有人写它，它都会将其发送给列表中包含的所有客户端。我如何做到这一点，使其不将消息发送给正在发送信息的客户端？我一直在试图找出答案，但是我对此有些迷茫。这是代码：

import socket
import threading
from _thread import *
from threading import Thread

clients = {}

def message(c):
    while True:
        data = c.recv(1024).decode("utf-8")
        print("Recieved: " + str(data))
        if not data:
            print("Client Disconnected.")
            break

        # skicka meddelanden till client
        for client in clients.values():
            try:
                client.sendall(data.encode("utf-8"))
            except ConnectionAbortedError:
                print("[!] Connection aborted ")
            except ConnectionResetError:
                print("[!] Connection reset error ")

def listener():
    host = "192.168.1.77"
    port = 22050
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    s.bind((host, port))
    s.listen(5)
    print("\nServer has started.\n\n" + "Host: " + host + "\nPort: " + str(port))
    print("______________________________________________________________________\n")
    while True:
        c, addr = s.accept()
        print(str(addr) + " has connected.")
        clients[c.fileno()] = c
        threading.Thread(target=message, args=(c,)).start()

if __name__ == '__main__':
    listener()

Answer 1

在if循环之后使用简单的for语句来检查迭代中的客户端是否等于线程中的当前客户端。如果是，请跳过它：

    # skicka meddelanden till client
    for client in clients.values():
        try:
            if client == c: # skip the current client
                continue
            client.sendall(data.encode("utf-8"))
        except ConnectionAbortedError:
            print("[!] Connection aborted ")
        except ConnectionResetError:
            print("[!] Connection reset error ")

如何将信息发送给所有客户端，而不发送给发件人？

1 个答案: