Question

我对编程很陌生。我正在尝试使用Beautiful Soup提取链接。

这是我汤的摘录。我想提取的是“ href”之后的链接。但是，我一直没有尝试过。

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我的想法是：

    for link in soup.find_all('div', attrs={'class': 'r'}):
    link = link.get('href')

Answer 1

也许您可以使用

from bs4 import BeautifulSoup
soup = BeautifulSoup(html_string, 'html.parser')
soup.find("div", class_="r").a['href']

因为类<div>中只有一个"r"，并且其中html_string是作为Python字符串的html源。

find()与class_参数一起使用以查找类<div>的{{1}}。然后访问其子项"r"的{{1}}属性。

所以输出应该是

<a>

从美丽汤中提取链接

1 个答案: