反序列化时出现JSONMappingException

时间:2019-01-03 23:56:51

标签: json serialization jackson deserialization jackson-databind

尝试反序列化时得到以下异常

com.fasterxml.jackson.databind.JsonMappingException: Unexpected token (END_OBJECT), expected FIELD_NAME: missing property '@class' that is to contain type id  (for class java.lang.Object)
        at [Source: [B@12fd6cc9; line: 1, column: 678]
        at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148)
        at com.fasterxml.jackson.databind.DeserializationContext.wrongTokenException(DeserializationContext.java:927)
        at com.fasterxml.jackson.databind.jsontype.impl.AsPropertyTypeDeserializer._deserializeTypedUsingDefaultImpl(AsPropertyTypeDeserializer.java:151)
        at com.fasterxml.jackson.databind.jsontype.impl.AsPropertyTypeDeserializer.deserializeTypedFromObject(AsPropertyTypeDeserializer.java:103)
        at com.fasterxml.jackson.databind.jsontype.impl.AsPropertyTypeDeserializer.deserializeTypedFromAny(AsPropertyTypeDeserializer.java:167)
        at com.fasterxml.jackson.databind.deser.std.UntypedObjectDeserializer$Vanilla.deserializeWithType(UntypedObjectDeserializer.java:500)
        at com.fasterxml.jackson.databind.deser.impl.TypeWrappedDeserializer.deserialize(TypeWrappedDeserializer.java:42)
        at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3562)
        at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2671)

如何在Object.class上使用@JSONTypeInfo? 我尝试如下设置对象映射器。但这不能解决错误。
mapper.enableDefaultTypingAsProperty(ObjectMapper.DefaultTyping.NON_FINAL,"@class");

我们将不胜感激。谢谢。

0 个答案:

没有答案
相关问题