Question

我在函数上有一个CustomEvent参数，我想获取事件的名称，即它是使用（new CustomEvent('foo')）构造的字符串

为了裁判https://developer.mozilla.org/en-US/docs/Web/API/CustomEvent

    public addEvent(iChannel: number, oEvent: CustomEvent)
    {
        if (App.isDebugging)
        {
            console.log(CustomEvent+' emitted '+CustomEvent.typeArg+' on channel '+iChannel);   
            console.log(CustomEvent);   
        }
        this.aEventChannels[iChannel].dispatchEvent(oEvent);
    }

//what lib.dom.d.ts says about this
declare var CustomEvent: {
    prototype: CustomEvent;
    new<T>(typeArg: string, eventInitDict?: CustomEventInit<T>): 
CustomEvent<T>;
};

我已经尝试过type和typeArg。两者都返回错误：

tsc --build src-webui/ts
src-webui/ts/App.ts(162,53): error TS2339: Property 'typeArg' does not exist on type '{ new <T>(typeArg: string, eventInitDict?: CustomEventInit<T> | undefined): CustomEvent<T>; prototype: CustomEvent<any>; }'.`

我将回到TS的发展阶段，所以我确定这很简单，正确的语法只是不“点击”我。

感谢任何指针，谢谢！

PS：这是针对浏览器的。

Answer 1

您似乎正在尝试获取.type类的CustomEvent属性，而不是获取传递给函数的oEvent对象。尝试改用此方法：

public addEvent(iChannel: number, oEvent: CustomEvent) {
    if (App.isDebugging) {
        console.log('Emitted ' + oEvent.type + ' on channel ' + iChannel);   
        console.log(oEvent);   
    }
    this.aEventChannels[iChannel].dispatchEvent(oEvent);
}

从CustomEvent获取事件的名称

1 个答案: