Question

我有一个包含表名的表（列名是表名-1000行）。我想遍历此表，构造一个select语句来访问每个表中的数据。我可以毫无问题地遍历表，但是找不到将内容（表的实际名称）插入到select语句中的方法。

...
hold_tablename = a_rec.tablename;
query1 := 'SELECT * FROM hold_tablename'; 
--  Postgres thinks 'hold_tablename' is the name of the table rather than
-- looking into the content of that field which should be aaa_customer_tbl.

<<innerloop>> 
FOR b_rec IN EXECUTE query1
loop
   select * from b_rec;
end loop innerloop;

Answer 1

将标识符插值到字符串中的最干净的方法是将format与Option Explicit Sub DivideSomeStuff() Const NUMBER_TO_CHANGE As Long = 7 ' Change this as needed Dim remainder As Long Dim pair As Range For Each pair In Range("B30, F30, J30") If Right(pair, Len(CStr(NUMBER_TO_CHANGE))) = NUMBER_TO_CHANGE Then If pair.Offset(0, 2) <= 12 Then remainder = 0 Else remainder = pair.Offset(0, 2) Mod 12 End If Dim findFifteen As Double findFifteen = (pair.Offset(0, 2) - remainder) / 10 Dim accumulator As Range For Each accumulator In Range("A36, D36, G36, J36, M36, A40, D40, G40, J40, M40") If accumulator.Offset(-1, 0) = Val(Left(pair, InStr(pair, "-") - 1)) Then accumulator.Value = accumulator.Value + remainder End If accumulator.Value = accumulator.Value + findFifteen Next accumulator End If Next pair End Sub指定符一起使用：

%I

在区分大小写或包含空格或其他有问题的字符的情况下，它将适当地引用query1 := format('SELECT * FROM %I', hold_tablename);。

或者，您可以使用hold_tablename和字符串串联：

quote_ident

但是query1 := 'SELECT * FROM ' || quote_ident(hold_tablename);的噪音较小。

PostgreSQL：选择表，其中表名作为内容存储在另一个表中

1 个答案: